Diffraction Gratings — Question 7

Section 36-7 · Physics pages 5984–5985

Question 7 Different spectral orders can place different wavelengths at the same angle A normally illuminated grating has spacing d = 2.00 µm. Its source includes wavelengths from 400 to 700 nm. Orders m and n overlap when mλm = nλn. d N illuminated slits 3λA = 2λB Schematic; labels, not drawing lengths, specify the data. (a) Find the shared angle of 400 nm in third order and 600 nm in second order. (b) Find the second-order wavelength interval whose directions overlap some third-order wavelength in the stated source band.
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Question 7 - Solution Different spectral orders can place different wavelengths at the same angle d N illuminated slits 3λA = 2λB (a) Method and calculation 3(400) = 2(600) = 1200 nm =⇒sin θ = 1200/2000. θ = 36.8699◦. (b) Interpretation and further calculation 2λ2 = 3λ3, 400 ≤λ3 ≤700 =⇒600 ≤λ2 ≤1050 nm. λ2 ∈[400, 700] =⇒λ2 ∈[600, 700] nm, λ3 ∈[400, 466.667] nm . Physical check A measured angle alone does not identify wavelength unless the order is known or unwanted orders are filtered.

Question 7

Different spectral orders can place different wavelengths at the same angle

A normally illuminated grating has spacing d=2.00μmd=2.00\,\mu\mathrm m. Its source includes wavelengths from 400 to 700nm700\,\mathrm{nm}. Orders m and n overlap when mλm=nλnm\lambda_m=n\lambda_n.

Diagram shown in the original SVG worksheet.

  1. Find the shared angle of 400nm400\,\mathrm{nm} in third order and 600nm600\,\mathrm{nm} in second order.

  2. Find the second-order wavelength interval whose directions overlap some third-order wavelength in the stated source band.

Question 7 - Solution

Different spectral orders can place different wavelengths at the same angle

Diagram shown in the original SVG worksheet.

(a) Method and calculation

3(400)=2(600)=1200nm⇒sin⁡θ=1200/2000.3(400)=2(600)=1200\,\mathrm{nm}\Longrightarrow\sin\theta=1200/2000.θ=36.8699∘.\boxed{\theta=36.8699^\circ}.

(b) Interpretation and further calculation

2λ2=3λ3,400≤λ3≤700⇒600≤λ2≤1050nm.2\lambda_2=3\lambda_3,\quad400\leq\lambda_3\leq700\Longrightarrow600\leq\lambda_2\leq1050\,\mathrm{nm}.λ2∈[400,700]⇒λ2∈[600,700]nm,λ3∈[400,466.667]nm.\lambda_2\in[400,700]\Longrightarrow\boxed{\lambda_2\in[600,700]\,\mathrm{nm},\quad\lambda_3\in[400,466.667]\,\mathrm{nm}}.

Physical check

A measured angle alone does not identify wavelength unless the order is known or unwanted orders are filtered.