Three Proofs — Question 10

Section 34-8 · Physics pages 5710–5711

Question 10 Stationary optical path gives an independent proof of spherical refraction An axial real object at x=-p and real image at x=q are separated by a spherical interface with vertex x=0 and radius R positive. Indices before and after are n1 and n2. At small ray height h, surface sag is z(h) ≃h2/(2R). Expand optical path through order h squared. C n1 n2 V (z, h) Schematic; labels, not drawing lengths, specify the data. (a) Expand the two geometric path lengths and their index-weighted sum. (b) Impose stationarity for neighboring paraxial rays and recover the spherical refraction relation.
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Question 10 - Solution Stationary optical path gives an independent proof of spherical refraction C n1 n2 V (z, h) (a) Method and calculation ℓ1 = √ (p + z)2 + h2 ≃p + z + h2/(2p), ℓ2 ≃q −z + h2/(2q). L = n1ℓ1 + n2ℓ2 ≃n1p + n2q + h2 2 [n1 p + n2 q + n1 −n2 R ] . (b) Interpretation and further calculation dL dh ≃h [n1 p + n2 q + n1 −n2 R ] = 0 for neighboring h̸ = 0. n1 p + n2 q = n2 −n1 R . Physical check The surface sag is second order in height and must be retained in this optical-path proof, even though the ray-angle proof neglects it at first order.

Question 10

Stationary optical path gives an independent proof of spherical refraction

An axial real object at x=-p and real image at x=q are separated by a spherical interface with vertex x=0 and radius R positive. Indices before and after are n1 and n2. At small ray height h, surface sag is z(h)≃h2/(2R)z(h)\simeq h^2/(2R). Expand optical path through order h squared.

Diagram shown in the original SVG worksheet.

  1. Expand the two geometric path lengths and their index-weighted sum.

  2. Impose stationarity for neighboring paraxial rays and recover the spherical refraction relation.

Question 10 - Solution

Stationary optical path gives an independent proof of spherical refraction

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ℓ1=(p+z)2+h2≃p+z+h2/(2p),ℓ2≃q−z+h2/(2q).\ell_1=\sqrt{(p+z)^2+h^2}\simeq p+z+h^2/(2p),\quad\ell_2\simeq q-z+h^2/(2q).ℒ=n1ℓ1+n2ℓ2≃n1p+n2q+h22[n1p+n2q+n1−n2R].\mathcal L=n_1\ell_1+n_2\ell_2\simeq n_1p+n_2q+\frac{h^2}{2}\left[\frac{n_1}{p}+\frac{n_2}{q}+\frac{n_1-n_2}{R}\right].

(b) Interpretation and further calculation

dℒdh≃h[n1p+n2q+n1−n2R]=0for neighboring h≠0.\frac{d\mathcal L}{dh}\simeq h\left[\frac{n_1}{p}+\frac{n_2}{q}+\frac{n_1-n_2}{R}\right]=0\quad\text{for neighboring }h\ne0.n1p+n2q=n2−n1R.\boxed{\frac{n_1}{p}+\frac{n_2}{q}=\frac{n_2-n_1}{R}}.

Physical check

The surface sag is second order in height and must be retained in this optical-path proof, even though the ray-angle proof neglects it at first order.