Three Proofs — Question 9

Section 34-8 · Physics pages 5708–5709

Question 9 Opposite lens powers can cancel a color-dependent focus shift Two thin lenses in contact in air have shape factors G1 and G2 and powers (n1 −1)G1 and (n2 −1)G2. At a reference color, n1=1.50 and n2=1.60. At a second color the index increments are 0.010 and 0.020. Require total power 5 inverse meters at both colors. G1 > 0 G2 < 0 Schematic; labels, not drawing lengths, specify the data. (a) Derive the two linear equations for the shape factors. (b) Solve for the shape factors and the individual reference-color powers, then verify cancellation of the color shift.
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Question 9 - Solution Opposite lens powers can cancel a color-dependent focus shift G1 > 0 G2 < 0 (a) Method and calculation 0.50G1 + 0.60G2 = 5 m−1 . ∆P = 0.010G1 + 0.020G2 = 0 ⇒G1 = −2G2. (b) Interpretation and further calculation G1 = 25 m−1, G2 = −12.5 m−1 ; P1 = 12.5, P2 = −7.5 m−1 . ∆P = 0.010(25) + 0.020(−12.5) = 0, ftotal = 0.20 m . Physical check The lenses must have opposite powers in this model. Matching these two colors does not establish perfect correction over an entire spectrum.

Question 9

Opposite lens powers can cancel a color-dependent focus shift

Two thin lenses in contact in air have shape factors G1 and G2 and powers (n1−1)G1(n_1-1)G_1 and (n2−1)G2(n_2-1)G_2. At a reference color, n1=1.50 and n2=1.60. At a second color the index increments are 0.010 and 0.020. Require total power 5 inverse meters at both colors.

Diagram shown in the original SVG worksheet.

  1. Derive the two linear equations for the shape factors.

  2. Solve for the shape factors and the individual reference-color powers, then verify cancellation of the color shift.

Question 9 - Solution

Opposite lens powers can cancel a color-dependent focus shift

Diagram shown in the original SVG worksheet.

(a) Method and calculation

0.50G1+0.60G2=5m−1.\boxed{0.50G_1+0.60G_2=5\,\mathrm{m^{-1}}}.Δ𝒫=0.010G1+0.020G2=0⇒G1=−2G2.\boxed{\Delta\mathcal P=0.010G_1+0.020G_2=0}\Rightarrow G_1=-2G_2.

(b) Interpretation and further calculation

G1=25m−1,G2=−12.5m−1;𝒫1=12.5,𝒫2=−7.5m−1.\boxed{G_1=25\,\mathrm{m^{-1}},\quad G_2=-12.5\,\mathrm{m^{-1}}};\quad\boxed{\mathcal P_1=12.5,\ \mathcal P_2=-7.5\,\mathrm{m^{-1}}}.Δ𝒫=0.010(25)+0.020(−12.5)=0,ftotal=0.20m.\boxed{\Delta\mathcal P=0.010(25)+0.020(-12.5)=0,\quad f_{\mathrm{total}}=0.20\,\mathrm m}.

Physical check

The lenses must have opposite powers in this model. Matching these two colors does not establish perfect correction over an entire spectrum.