Polarization by Reflection — Question 5

Section 33-9 · Physics pages 5540–5541

Question 5 Angular uncertainty becomes an index uncertainty in a Brewster measurement A transparent sample in air has measured Brewster angle 57.0 degrees with small uncertainty 0.2 degrees. Assume the air index is exactly one and the interface obeys the nonmagnetic lossless model. θB n Schematic; labels, not drawing lengths, specify the data. (a) Infer the sample index and propagate the angular uncertainty to first order. (b) Find the relative index uncertainty and state the required angular unit in the derivative.
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Question 5 - Solution Angular uncertainty becomes an index uncertainty in a Brewster measurement θB n (a) Method and calculation n = tan θB = tan 57.0◦= 1.53986 . σn ≃ dn dθB σθ = sec2 θB σθ. (b) Interpretation and further calculation σθ = 0.2π/180 = 0.00349066 rad ⇒σn = 0.0117677 . σn/n = 0.00764200 ≃0.764% ; n ≃1.540 ± 0.012. Physical check The derivative of tangent is taken with its angle in radians; substituting a degree value directly would overestimate the uncertainty.

Question 5

Angular uncertainty becomes an index uncertainty in a Brewster measurement

A transparent sample in air has measured Brewster angle 57.0 degrees with small uncertainty 0.2 degrees. Assume the air index is exactly one and the interface obeys the nonmagnetic lossless model.

Diagram shown in the original SVG worksheet.

  1. Infer the sample index and propagate the angular uncertainty to first order.

  2. Find the relative index uncertainty and state the required angular unit in the derivative.

Question 5 - Solution

Angular uncertainty becomes an index uncertainty in a Brewster measurement

Diagram shown in the original SVG worksheet.

(a) Method and calculation

n=tan⁡θB=tan⁡57.0∘=1.53986.\boxed{n=\tan\theta_B=\tan57.0^\circ=1.53986}.σn≃|dndθB|σθ=sec⁡2θBσθ.\sigma_n\simeq\left|\frac{dn}{d\theta_B}\right|\sigma_\theta=\sec^2\theta_B\,\sigma_\theta.

(b) Interpretation and further calculation

σθ=0.2π/180=0.00349066rad⇒σn=0.0117677.\sigma_\theta=0.2\pi/180=0.00349066\,\mathrm{rad}\Rightarrow\boxed{\sigma_n=0.0117677}.σn/n=0.00764200≃0.764%;n≃1.540±0.012.\boxed{\sigma_n/n=0.00764200\simeq0.764\%};\quad n\simeq1.540\pm0.012.

Physical check

The derivative of tangent is taken with its angle in radians; substituting a degree value directly would overestimate the uncertainty.