Polarization by Reflection — Question 4

Section 33-9 · Physics pages 5538–5539

Question 4 Brewster transmission is generally only partly polarized An unpolarized beam of power P0 strikes a single lossless interface at Brewster incidence. Its s reflectance is Rs and its p reflectance is zero. A detector collects the entire transmitted beam. Define the transmitted degree of linear polarization as the power difference divided by the sum. n1 n2 both s, p Schematic; labels, not drawing lengths, specify the data. (a) Find the transmitted s and p powers and total transmitted power. (b) Derive the degree of polarization and evaluate it when Rs=1/4.
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Question 4 - Solution Brewster transmission is generally only partly polarized n1 n2 both s, p (a) Method and calculation Pt,p = P0/2, Pt,s = (1 −Rs)P0/2 . Pt = P0(1 −Rs/2) . (b) Interpretation and further calculation Pt = Pt,p −Pt,s Pt,p + Pt,s = Rs 2 −Rs . Rs = 1/4 ⇒Pt/P0 = 7/8, Pt = 1/7 . Physical check The reflected beam is purely s, but the transmitted beam retains both components unless s transmission also vanishes.

Question 4

Brewster transmission is generally only partly polarized

An unpolarized beam of power P0 strikes a single lossless interface at Brewster incidence. Its s reflectance is Rs and its p reflectance is zero. A detector collects the entire transmitted beam. Define the transmitted degree of linear polarization as the power difference divided by the sum.

Diagram shown in the original SVG worksheet.

  1. Find the transmitted s and p powers and total transmitted power.

  2. Derive the degree of polarization and evaluate it when Rs=1/4.

Question 4 - Solution

Brewster transmission is generally only partly polarized

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Pt,p=P0/2,Pt,s=(1−Rs)P0/2.\boxed{P_{t,p}=P_0/2,\quad P_{t,s}=(1-R_s)P_0/2}.Pt=P0(1−Rs/2).\boxed{P_t=P_0(1-R_s/2)}.

(b) Interpretation and further calculation

𝒫t=Pt,p−Pt,sPt,p+Pt,s=Rs2−Rs.\mathcal P_t=\frac{P_{t,p}-P_{t,s}}{P_{t,p}+P_{t,s}}=\boxed{\frac{R_s}{2-R_s}}.Rs=1/4⇒Pt/P0=7/8,𝒫t=1/7.R_s=1/4\Rightarrow\boxed{P_t/P_0=7/8,\quad\mathcal P_t=1/7}.

Physical check

The reflected beam is purely s, but the transmitted beam retains both components unless s transmission also vanishes.