Total Internal Reflection — Question 7

Section 33-8 · Physics pages 5524–5525

Question 7 Changing a narrow gap can modulate evanescent coupling exponentially Two high-index prisms are separated by a low-index gap of width d. For sufficiently weak coupling, use the supplied model T(d) = Ce−2κd, with positive constants C and kappa independent of d. This is an approximate power-transmission model, not the full boundary solution. d evanescent gap field Schematic; labels, not drawing lengths, specify the data. (a) Find the gap increase needed to reduce transmission by a factor of ten. (b) Find the fractional transmission change for a small displacement delta d, and evaluate the tenfold gap increase for kappa inverse equal to 120 nm.
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Question 7 - Solution Changing a narrow gap can modulate evanescent coupling exponentially d evanescent gap field (a) Method and calculation T(d + ∆d) T(d) = e−2κ∆d = 1/10. ∆d = ln 10/(2κ) . (b) Interpretation and further calculation δT/T ≃−2κ δd (|κδd| ≪1). ∆d = (120 nm) ln 10/2 = 138.155 nm . Physical check Ratios remove the unknown prefactor C. Extrapolating this weak-coupling model to a vanishing gap is not justified.

Question 7

Changing a narrow gap can modulate evanescent coupling exponentially

Two high-index prisms are separated by a low-index gap of width d. For sufficiently weak coupling, use the supplied model T(d)=Ce−2κdT(d)=C e^{-2\kappa d}, with positive constants C and kappa independent of d. This is an approximate power-transmission model, not the full boundary solution.

Diagram shown in the original SVG worksheet.

  1. Find the gap increase needed to reduce transmission by a factor of ten.

  2. Find the fractional transmission change for a small displacement delta d, and evaluate the tenfold gap increase for kappa inverse equal to 120 nm.

Question 7 - Solution

Changing a narrow gap can modulate evanescent coupling exponentially

Diagram shown in the original SVG worksheet.

(a) Method and calculation

T(d+Δd)T(d)=e−2κΔd=1/10.\frac{T(d+\Delta d)}{T(d)}=e^{-2\kappa\Delta d}=1/10.Δd=ln⁡10/(2κ).\boxed{\Delta d=\ln10/(2\kappa)}.

(b) Interpretation and further calculation

δT/T≃−2κδd(|κδd|≪1).\boxed{\delta T/T\simeq-2\kappa\,\delta d}\quad(|\kappa\delta d|\ll1).Δd=(120nm)ln⁡10/2=138.155nm.\boxed{\Delta d=(120\,\mathrm{nm})\ln10/2=138.155\,\mathrm{nm}}.

Physical check

Ratios remove the unknown prefactor C. Extrapolating this weak-coupling model to a vanishing gap is not justified.