Radiation Pressure — Question 4

Section 33-5 · Physics pages 5458–5459

Question 4 A short pulse gives a mirror an impulse before appreciable displacement A pulse of energy U strikes a free perfect mirror of mass M normally in vacuum. Initially the mirror is at rest and U is much smaller than Mc squared. Work to leading nonzero order in this small ratio. I area A free mass M Schematic; labels, not drawing lengths, specify the data. (a) Find mirror impulse and recoil speed, comparing with an absorber. (b) Find the leading recoil kinetic energy and its fraction of incident energy.
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Question 4 - Solution A short pulse gives a mirror an impulse before appreciable displacement I area A free mass M (a) Method and calculation Jmirror ≃2U/c, v ≃2U/(Mc) . Jabsorber ≃U/c, Jmirror/Jabsorber ≃2. (b) Interpretation and further calculation K ≃J2 2M = 2U2 Mc2 . K/U ≃2U/(Mc2) ≪1 , Ureflected = U −K. Physical check Treating reflected energy as U is sufficient for the leading impulse; the small energy difference supplies recoil kinetic energy.

Question 4

A short pulse gives a mirror an impulse before appreciable displacement

A pulse of energy U strikes a free perfect mirror of mass M normally in vacuum. Initially the mirror is at rest and U is much smaller than Mc squared. Work to leading nonzero order in this small ratio.

Diagram shown in the original SVG worksheet.

  1. Find mirror impulse and recoil speed, comparing with an absorber.

  2. Find the leading recoil kinetic energy and its fraction of incident energy.

Question 4 - Solution

A short pulse gives a mirror an impulse before appreciable displacement

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Jmirror≃2U/c,v≃2U/(Mc).J_{\mathrm{mirror}}\simeq2U/c,\quad\boxed{v\simeq2U/(Mc)}.Jabsorber≃U/c,Jmirror/Jabsorber≃2.J_{\mathrm{absorber}}\simeq U/c,\quad J_{\mathrm{mirror}}/J_{\mathrm{absorber}}\simeq2.

(b) Interpretation and further calculation

K≃J22M=2U2Mc2.K\simeq\frac{J^2}{2M}=\boxed{\frac{2U^2}{Mc^2}}.K/U≃2U/(Mc2)≪1,Ureflected=U−K.\boxed{K/U\simeq2U/(Mc^2)\ll1},\quad U_{\mathrm{reflected}}=U-K.

Physical check

Treating reflected energy as U is sufficient for the leading impulse; the small energy difference supplies recoil kinetic energy.