Radiation Pressure — Question 3

Section 33-5 · Physics pages 5456–5457

Question 3 An oblique absorber receives a tangential radiation force A black stationary plate of area A absorbs a vacuum beam of intensity I incident at angle theta from its inward normal. Let n point normally into the plate and t point along the incident tangential component. Ignore thermal reradiation during the measurement. ˆn ˆt Schematic; labels, not drawing lengths, specify the data. (a) Find the vector force and its normal and tangential components. (b) Find the ratio of tangential to normal force at 30 degrees and compare the normal force to a perfect mirror.
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Question 3 - Solution An oblique absorber receives a tangential radiation force ˆn ˆt (a) Method and calculation ˆk = cos θ ˆn + sin θ ˆt, F = IA cos θ c ˆk. Fn = IA cos2 θ/c, Ft = IA sin θ cos θ/c . (b) Interpretation and further calculation Ft/Fn = tan 30◦= 1/ √ 3 . Fn,abs/Fn,mirror = 1/2 . Physical check Absorption removes both components of incident momentum; a specular mirror reverses only the normal component.

Question 3

An oblique absorber receives a tangential radiation force

A black stationary plate of area A absorbs a vacuum beam of intensity I incident at angle theta from its inward normal. Let n point normally into the plate and t point along the incident tangential component. Ignore thermal reradiation during the measurement.

Diagram shown in the original SVG worksheet.

  1. Find the vector force and its normal and tangential components.

  2. Find the ratio of tangential to normal force at 30 degrees and compare the normal force to a perfect mirror.

Question 3 - Solution

An oblique absorber receives a tangential radiation force

Diagram shown in the original SVG worksheet.

(a) Method and calculation

k̂=cos⁡θn̂+sin⁡θt̂,𝑭=IAcos⁡θck̂.\hat k=\cos\theta\,\hat n+\sin\theta\,\hat t,\quad\mathbf F=\frac{IA\cos\theta}{c}\hat k.Fn=IAcos⁡2θ/c,Ft=IAsin⁡θcos⁡θ/c.\boxed{F_n=IA\cos^2\theta/c,\quad F_t=IA\sin\theta\cos\theta/c}.

(b) Interpretation and further calculation

Ft/Fn=tan⁡30∘=1/3.\boxed{F_t/F_n=\tan30^\circ=1/\sqrt3}.Fn,abs/Fn,mirror=1/2.\boxed{F_{n,\mathrm{abs}}/F_{n,\mathrm{mirror}}=1/2}.

Physical check

Absorption removes both components of incident momentum; a specular mirror reverses only the normal component.