Paramagnetism — Question 9

Section 32-9 · Physics pages 5348–5349

Question 9 An inverse-susceptibility line determines a Curie-Weiss intercept A material in its high-temperature paramagnetic regime follows χ = C/(T −Θ). Measurements give χ = 0.020 at 300 K and χ = 0.010 at 400 K. Restrict use of this model to the measured regime. T 1/χ Θ Schematic; labels, not drawing lengths, specify the data. (a) Find C and Theta from the two measurements. (b) Predict susceptibility at 500 K and give the slope and temperature-axis intercept of a plot of inverse susceptibility versus T.
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Question 9 - Solution An inverse-susceptibility line determines a Curie-Weiss intercept T 1/χ Θ (a) Method and calculation 0.020(300 −Θ) = 0.010(400 −Θ) ⇒Θ = 200 K . C = 0.020(300 −200) = 2.00 K . (b) Interpretation and further calculation χ(500) = 2/(500 −200) = 6.667 × 10−3 . χ−1 = (T −Θ)/C ⇒slope = 0.500 K−1, T intercept = 200 K . Physical check The extrapolated intercept alone does not validate the model near a phase transition or prove that the actual transition occurs there.

Question 9

An inverse-susceptibility line determines a Curie-Weiss intercept

A material in its high-temperature paramagnetic regime follows χ=C/(T−Θ)\chi=C/(T-\Theta). Measurements give χ=0.020\chi=0.020 at 300 K and χ=0.010\chi=0.010 at 400 K. Restrict use of this model to the measured regime.

Diagram shown in the original SVG worksheet.

  1. Find C and Theta from the two measurements.

  2. Predict susceptibility at 500 K and give the slope and temperature-axis intercept of a plot of inverse susceptibility versus T.

Question 9 - Solution

An inverse-susceptibility line determines a Curie-Weiss intercept

Diagram shown in the original SVG worksheet.

(a) Method and calculation

0.020(300−Θ)=0.010(400−Θ)⇒Θ=200K.0.020(300-\Theta)=0.010(400-\Theta)\Rightarrow\boxed{\Theta=200\,\mathrm K}.C=0.020(300−200)=2.00K.\boxed{C=0.020(300-200)=2.00\,\mathrm K}.

(b) Interpretation and further calculation

χ(500)=2/(500−200)=6.667×10−3.\boxed{\chi(500)=2/(500-200)=6.667\times10^{-3}}.χ−1=(T−Θ)/C⇒slope=0.500K−1,T intercept=200K.\chi^{-1}=(T-\Theta)/C\Rightarrow\boxed{\text{slope}=0.500\,\mathrm{K^{-1}},\quad T\text{ intercept}=200\,\mathrm K}.

Physical check

The extrapolated intercept alone does not validate the model near a phase transition or prove that the actual transition occurs there.