Magnets — Question 3

Section 32-5 · Physics pages 5256–5257

Question 3 A compass calibration separates two perpendicular field components A horizontal compass sees an unknown field BE ˆy and a coil field kIˆx. Its equilibrium deflection from +y is 30◦at current I0. Ignore other fields. kI BE Btotal θ Schematic; labels, not drawing lengths, specify the data. (a) Find BE in terms of k and I0. (b) At current 2I0 find the deflection and the ratio of total field magnitudes at the two currents.
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Question 3 - Solution A compass calibration separates two perpendicular field components kI BE Btotal θ (a) Method and calculation tan θ = kI BE ⇒BE = √ 3kI0 . B1 = √ B2 E + (kI0)2 = 2kI0. (b) Interpretation and further calculation θ2 = tan−1(2/ √ 3) = 49.1066◦. B2/B1 = √ 7/2 = 1.32288 . Physical check The angle does not double when current doubles because the compass follows the vector sum.

Question 3

A compass calibration separates two perpendicular field components

A horizontal compass sees an unknown field BEŷB_E\hat y and a coil field kIx̂kI\hat x. Its equilibrium deflection from +y is 30∘30^\circ at current I0. Ignore other fields.

Diagram shown in the original SVG worksheet.

  1. Find BE in terms of k and I0.

  2. At current 2I0 find the deflection and the ratio of total field magnitudes at the two currents.

Question 3 - Solution

A compass calibration separates two perpendicular field components

Diagram shown in the original SVG worksheet.

(a) Method and calculation

tan⁡θ=kIBE⇒BE=3kI0.\tan\theta=\frac{kI}{B_E}\Rightarrow\boxed{B_E=\sqrt3kI_0}.B1=BE2+(kI0)2=2kI0.B_1=\sqrt{B_E^2+(kI_0)^2}=2kI_0.

(b) Interpretation and further calculation

θ2=tan⁡−1(2/3)=49.1066∘.\theta_2=\tan^{-1}(2/\sqrt3)=49.1066^\circ.B2/B1=7/2=1.32288.\boxed{B_2/B_1=\sqrt7/2=1.32288}.

Physical check

The angle does not double when current doubles because the compass follows the vector sum.