Magnets — Question 2

Section 32-5 · Physics pages 5254–5255

Question 2 Rotation work and torque provide independent tests of a magnet moment A permanent dipole of fixed magnitude m rotates quasistatically in a uniform field B. Positive external work W is needed to turn it from 0 to 120◦. B m θ Schematic; labels, not drawing lengths, specify the data. (a) Infer m from W and B using potential energy. (b) Find the magnetic torque magnitude at 120◦and the work recovered on returning to 0.
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Question 2 - Solution Rotation work and torque provide independent tests of a magnet moment B m θ (a) Method and calculation W = Uf −Ui = −mB cos 120◦+ mB = 3 2mB. m = 2W/(3B) . (b) Interpretation and further calculation |τ| = mB sin 120◦= (2W/3)( √ 3/2). |τ| = W/ √ 3, Wrecovered = W . Physical check Torque and work both have SI unit joule, but torque is a rotational tendency and work is an energy transfer.

Question 2

Rotation work and torque provide independent tests of a magnet moment

A permanent dipole of fixed magnitude m rotates quasistatically in a uniform field B. Positive external work W is needed to turn it from 0 to 120∘120^\circ.

Diagram shown in the original SVG worksheet.

  1. Infer m from W and B using potential energy.

  2. Find the magnetic torque magnitude at 120∘120^\circ and the work recovered on returning to 0.

Question 2 - Solution

Rotation work and torque provide independent tests of a magnet moment

Diagram shown in the original SVG worksheet.

(a) Method and calculation

W=Uf−Ui=−mBcos⁡120∘+mB=32mB.W=U_f-U_i=-mB\cos120^\circ+mB=\tfrac32mB.m=2W/(3B).\boxed{m=2W/(3B)}.

(b) Interpretation and further calculation

|τ|=mBsin⁡120∘=(2W/3)(3/2).|\tau|=mB\sin120^\circ=(2W/3)(\sqrt3/2).|τ|=W/3,Wrecovered=W.\boxed{|\tau|=W/\sqrt3,\qquad W_{\mathrm{recovered}}=W}.

Physical check

Torque and work both have SI unit joule, but torque is a rotational tendency and work is an energy transfer.