Ferromagnetism — Question 9

Section 32-10 · Physics pages 5368–5369

Question 9 Competing wall and stray-field energies favor a finite domain count A toy model for n domains in a specimen assigns energy E(n) = an + b/n, with positive constants a and b. Treat n as continuous for minimization, then compare adjacent integers. The first term represents domain-wall cost and the second stray-field energy. illustration: five domains more walls; reduced stray-field energy Schematic; labels, not drawing lengths, specify the data. (a) Find the continuous optimum and minimum energy, and verify it is a minimum. (b) For b/a=20, compare n=4 and n=5. Explain why neither a single domain nor infinitely many domains is automatically favored.
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Question 9 - Solution Competing wall and stray-field energies favor a finite domain count illustration: five domains more walls; reduced stray-field energy (a) Method and calculation dE dn = a −b/n2 = 0 ⇒n∗= √ b/a . E′′ = 2b/n3 > 0, Emin = 2 √ ab . (b) Interpretation and further calculation b/a = 20 : E(4)/a = 4 + 20/4 = 9, E(5)/a = 5 + 20/5 = 9. n = 4 and n = 5 tie in this discrete model . Physical check Domains reduce stray-field energy but create walls; the supplied model balances these costs without claiming a universal domain geometry.

Question 9

Competing wall and stray-field energies favor a finite domain count

A toy model for n domains in a specimen assigns energy E(n)=an+b/nE(n)=an+b/n, with positive constants a and b. Treat n as continuous for minimization, then compare adjacent integers. The first term represents domain-wall cost and the second stray-field energy.

Diagram shown in the original SVG worksheet.

  1. Find the continuous optimum and minimum energy, and verify it is a minimum.

  2. For b/a=20, compare n=4 and n=5. Explain why neither a single domain nor infinitely many domains is automatically favored.

Question 9 - Solution

Competing wall and stray-field energies favor a finite domain count

Diagram shown in the original SVG worksheet.

(a) Method and calculation

dEdn=a−b/n2=0⇒n*=b/a.\frac{dE}{dn}=a-b/n^2=0\Rightarrow\boxed{n_*=\sqrt{b/a}}.E′′=2b/n3>0,Emin=2ab.E^{\prime\prime}=2b/n^3>0,\quad\boxed{E_{\min}=2\sqrt{ab}}.

(b) Interpretation and further calculation

b/a=20:E(4)/a=4+20/4=9,E(5)/a=5+20/5=9.b/a=20:\quad E(4)/a=4+20/4=9,\quad E(5)/a=5+20/5=9.n=4 and n=5 tie in this discrete model.\boxed{n=4\text{ and }n=5\text{ tie in this discrete model}}.

Physical check

Domains reduce stray-field energy but create walls; the supplied model balances these costs without claiming a universal domain geometry.