Damped Oscillations in an RLC Circuit — Question 8

Section 31-4 · Physics pages 5046–5047

Question 8 Distributed series resistance shares all the eventual oscillator heat A source-free series RLC loop has initial charge Q0, initial current I0, and two positive resistances R1 and R2 in series. All components are constant and ideal except these resistances. R1 + R2 C L q i = ˙q Schematic; labels, not drawing lengths, specify the data. (a) Find the eventual heat in each resistor. (b) Find how the partition changes if R1 is doubled with R2 fixed, without solving q(t).
Show solutionHide solution
Question 8 - Solution Distributed series resistance shares all the eventual oscillator heat R1 + R2 C L q i = ˙q (a) Method and calculation U0 = Q2 0/(2C) + LI2 0/2, ∫∞ 0 i2(R1 + R2)dt = U0. H1 = R1 R1 + R2 U0, H2 = R2 R1 + R2 U0 . (b) Interpretation and further calculation R1 →2R1 : Hnew 1 = 2R1 2R1 + R2 U0. Hnew 1 /H1 = 2(R1 + R2) 2R1 + R2 . Physical check The time history changes with resistance, but the common-current heat ratio remains fixed.

Question 8

Distributed series resistance shares all the eventual oscillator heat

A source-free series RLC loop has initial charge Q0, initial current I0, and two positive resistances R1 and R2 in series. All components are constant and ideal except these resistances.

Diagram shown in the original SVG worksheet.

  1. Find the eventual heat in each resistor.

  2. Find how the partition changes if R1 is doubled with R2 fixed, without solving q(t).

Question 8 - Solution

Distributed series resistance shares all the eventual oscillator heat

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U0=Q02/(2C)+LI02/2,∫0∞i2(R1+R2)dt=U0.U_0=Q_0^2/(2C)+LI_0^2/2,\quad\int_0^\infty i^2(R_1+R_2)dt=U_0.H1=R1R1+R2U0,H2=R2R1+R2U0.\boxed{H_1=\frac{R_1}{R_1+R_2}U_0,\quad H_2=\frac{R_2}{R_1+R_2}U_0}.

(b) Interpretation and further calculation

R1→2R1:H1new=2R12R1+R2U0.R_1\to2R_1:\quad H_1^{\mathrm{new}}=\frac{2R_1}{2R_1+R_2}U_0.H1new/H1=2(R1+R2)2R1+R2.\boxed{H_1^{\mathrm{new}}/H_1=\frac{2(R_1+R_2)}{2R_1+R_2}}.

Physical check

The time history changes with resistance, but the common-current heat ratio remains fixed.