Damped Oscillations in an RLC Circuit — Question 7

Section 31-4 · Physics pages 5044–5045

Question 7 A required number of visible cycles imposes a resistance limit An underdamped oscillator must retain at least one-half its initial charge-envelope amplitude after N damped cycles. Define ζ = R/(2 √ L/C). ωt q/Q0 Schematic; labels, not drawing lengths, specify the data. (a) Derive an exact upper bound on zeta. (b) Evaluate the bound for N=10 and express the corresponding R limit.
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Question 7 - Solution A required number of visible cycles imposes a resistance limit ωt q/Q0 (a) Method and calculation e−αNTd ≥1/2, αTd = 2πζ √ 1 −ζ2 . ζ ≤ ln 2 √ (2πN)2 + (ln 2)2 . (b) Interpretation and further calculation N = 10 ⇒ζmax = .0110311. R ≤2(.0110311) √ L/C . Physical check The exact bound uses the damped period; weak-damping approximations are unnecessary here.

Question 7

A required number of visible cycles imposes a resistance limit

An underdamped oscillator must retain at least one-half its initial charge-envelope amplitude after N damped cycles. Define ζ=R/(2L/C)\zeta=R/(2\sqrt{L/C}).

Diagram shown in the original SVG worksheet.

  1. Derive an exact upper bound on zeta.

  2. Evaluate the bound for N=10 and express the corresponding R limit.

Question 7 - Solution

A required number of visible cycles imposes a resistance limit

Diagram shown in the original SVG worksheet.

(a) Method and calculation

e−αNTd≥1/2,αTd=2πζ1−ζ2.e^{-\alpha NT_d}\ge1/2,\quad\alpha T_d=\frac{2\pi\zeta}{\sqrt{1-\zeta^2}}.ζ≤ln⁡2(2πN)2+(ln⁡2)2.\boxed{\zeta\le\frac{\ln2}{\sqrt{(2\pi N)^2+(\ln2)^2}}}.

(b) Interpretation and further calculation

N=10⇒ζmax=.0110311.N=10\Rightarrow\zeta_{\max}=.0110311.R≤2(.0110311)L/C.\boxed{R\le2(.0110311)\sqrt{L/C}}.

Physical check

The exact bound uses the damped period; weak-damping approximations are unnecessary here.