Damped Oscillations in an RLC Circuit — Question 4

Section 31-4 · Physics pages 5038–5039

Question 4 Large resistance creates a slow capacitive tail as well as a fast inductive transient An overdamped series RLC circuit has R2 ≫4L/C. Its charge modes are proportional to es±t. t q slow Schematic; labels, not drawing lengths, specify the data. (a) Find the exact roots and their large-R approximations. (b) Identify the two time constants and explain why increasing R does not make the slow discharge faster.
Show solutionHide solution
Question 4 - Solution Large resistance creates a slow capacitive tail as well as a fast inductive transient t q slow (a) Method and calculation Ls2 + Rs + 1/C = 0 ⇒s± = −R ± √ R2 −4L/C 2L . s+ ≃−1/(RC), s−≃−R/L . (b) Interpretation and further calculation τslow = −1/s+ ≃RC, τfast = −1/s−≃L/R. R ↑⇒τslow ↑, τfast ↓. Physical check Two distinct relaxation processes coexist; the late-time behavior is governed by the slower root.

Question 4

Large resistance creates a slow capacitive tail as well as a fast inductive transient

An overdamped series RLC circuit has R2≫4L/CR^2\gg4L/C. Its charge modes are proportional to es±te^{s_\pm t}.

Diagram shown in the original SVG worksheet.

  1. Find the exact roots and their large-R approximations.

  2. Identify the two time constants and explain why increasing R does not make the slow discharge faster.

Question 4 - Solution

Large resistance creates a slow capacitive tail as well as a fast inductive transient

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Ls2+Rs+1/C=0⇒s±=−R±R2−4L/C2L.Ls^2+Rs+1/C=0\Rightarrow s_\pm=\frac{-R\pm\sqrt{R^2-4L/C}}{2L}.s+≃−1/(RC),s−≃−R/L.\boxed{s_+\simeq-1/(RC),\quad s_-\simeq-R/L}.

(b) Interpretation and further calculation

τslow=−1/s+≃RC,τfast=−1/s−≃L/R.\tau_{\mathrm{slow}}=-1/s_+\simeq RC,\quad\tau_{\mathrm{fast}}=-1/s_-\simeq L/R.R↑⇒τslow↑,τfast↓.\boxed{R\uparrow\Rightarrow\tau_{\mathrm{slow}}\uparrow,\quad\tau_{\mathrm{fast}}\downarrow}.

Physical check

Two distinct relaxation processes coexist; the late-time behavior is governed by the slower root.