Damped Oscillations in an RLC Circuit — Question 3

Section 31-4 · Physics pages 5036–5037

Question 3 Critical damping reaches zero charge without crossing it after release from rest A series circuit has R = 2 √ L/C and is released from q = Q0 > 0, i = 0. Let ω0 = 1/ √ LC. t q Schematic; labels, not drawing lengths, specify the data. (a) Find q(t) from the repeated-root solution. (b) Find the time and magnitude of maximum current.
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Question 3 - Solution Critical damping reaches zero charge without crossing it after release from rest t q (a) Method and calculation q = (A + Bt)e−ω0t, A = Q0, B = ω0Q0. q = Q0(1 + ω0t)e−ω0t, i = −Q0ω2 0te−ω0t . (b) Interpretation and further calculation d dt|i| = Q0ω2 0e−ω0t(1 −ω0t) = 0. t|i| max = 1/ω0, |i|max = Q0ω0/e . Physical check For these initial conditions q stays positive and decreases monotonically.

Question 3

Critical damping reaches zero charge without crossing it after release from rest

A series circuit has R=2L/CR=2\sqrt{L/C} and is released from q=Q0>0q=Q_0>0, i=0i=0. Let ω0=1/LC\omega_0=1/\sqrt{LC}.

Diagram shown in the original SVG worksheet.

  1. Find q(t) from the repeated-root solution.

  2. Find the time and magnitude of maximum current.

Question 3 - Solution

Critical damping reaches zero charge without crossing it after release from rest

Diagram shown in the original SVG worksheet.

(a) Method and calculation

q=(A+Bt)e−ω0t,A=Q0,B=ω0Q0.q=(A+Bt)e^{-\omega_0t},\quad A=Q_0,\quad B=\omega_0Q_0.q=Q0(1+ω0t)e−ω0t,i=−Q0ω02te−ω0t.\boxed{q=Q_0(1+\omega_0t)e^{-\omega_0t},\quad i=-Q_0\omega_0^2t e^{-\omega_0t}}.

(b) Interpretation and further calculation

ddt|i|=Q0ω02e−ω0t(1−ω0t)=0.\frac d{dt}|i|=Q_0\omega_0^2e^{-\omega_0t}(1-\omega_0t)=0.t|i|max=1/ω0,|i|max=Q0ω0/e.\boxed{t_{|i|\max}=1/\omega_0,\quad |i|_{\max}=Q_0\omega_0/e}.

Physical check

For these initial conditions q stays positive and decreases monotonically.