Transformers — Question 9

Section 31-10 · Physics pages 5168–5169

Question 9 Stepping up transmission voltage reduces line loss quadratically Ideal transformers deliver 50.0 kW at unity power factor through a line of total resistance 20.0 ohms. Compare receiving-end line voltages 5.00 kV and 25.0 kV. Neglect transformer losses. up down line R load P Schematic; labels, not drawing lengths, specify the data. (a) Find line current and resistive loss in each case. (b) Find total transmission efficiency and the ratio of line losses.
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Question 9 - Solution Stepping up transmission voltage reduces line loss quadratically up down line R load P (a) Method and calculation I1 = P/V1 = 10.0 A, I2 = P/V2 = 2.00 A. Ploss,1 = 2000 W, Ploss,2 = 80.0 W . (b) Interpretation and further calculation η = P/(P + Ploss) ⇒η1 = 50000/52000, η2 = 50000/50080. η1 = .961538, η2 = .998403, Ploss,2/Ploss,1 = 1/25 . Physical check Receiving-end voltage is specified so current follows directly from delivered power; source power must also cover line heat.

Question 9

Stepping up transmission voltage reduces line loss quadratically

Ideal transformers deliver 50.0 kW at unity power factor through a line of total resistance 20.0 ohms. Compare receiving-end line voltages 5.00 kV and 25.0 kV. Neglect transformer losses.

Diagram shown in the original SVG worksheet.

  1. Find line current and resistive loss in each case.

  2. Find total transmission efficiency and the ratio of line losses.

Question 9 - Solution

Stepping up transmission voltage reduces line loss quadratically

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I1=P/V1=10.0A,I2=P/V2=2.00A.I_1=P/V_1=10.0\,A,\quad I_2=P/V_2=2.00\,A.Ploss,1=2000W,Ploss,2=80.0W.\boxed{P_{{\mathrm{loss}},1}=2000\,W,\quad P_{{\mathrm{loss}},2}=80.0\,W}.

(b) Interpretation and further calculation

η=P/(P+Ploss)⇒η1=50000/52000,η2=50000/50080.\eta=P/(P+P_{\mathrm{loss}})\Rightarrow\eta_1=50000/52000,\quad\eta_2=50000/50080.η1=.961538,η2=.998403,Ploss,2/Ploss,1=1/25.\boxed{\eta_1=.961538,\quad\eta_2=.998403,\quad P_{{\mathrm{loss}},2}/P_{{\mathrm{loss}},1}=1/25}.

Physical check

Receiving-end voltage is specified so current follows directly from delivered power; source power must also cover line heat.