Transformers — Question 8

Section 31-10 · Physics pages 5166–5167

Question 8 Secondary polarity controls whether series voltages add or subtract Two isolated secondary windings on the same ideal core have 40 and 60 turns. The induced rms voltage is .500 V per turn. Their dotted-to-undotted voltages are in phase. N1 = 40 N2 = 60 left ends dotted; common core Schematic; labels, not drawing lengths, specify the data. (a) Find the voltage across the free terminals when the undotted end of winding 1 is joined to the dotted end of winding 2. (b) Find the magnitude when the two undotted ends are instead joined, and explain the difference.
Show solutionHide solution
Question 8 - Solution Secondary polarity controls whether series voltages add or subtract N1 = 40 N2 = 60 left ends dotted; common core (a) Method and calculation V1 = (40)(.500) = 20.0 V, V2 = (60)(.500) = 30.0 V. Vaiding = V1 + V2 = 50.0 V . (b) Interpretation and further calculation Vd1 −Vd2 = V1 −V2 when undotted ends are common. |Vopposing| = |20 −30| = 10.0 V . Physical check Turn counts determine magnitudes; winding polarity determines the sign in the terminal sum.

Question 8

Secondary polarity controls whether series voltages add or subtract

Two isolated secondary windings on the same ideal core have 40 and 60 turns. The induced rms voltage is .500 V per turn. Their dotted-to-undotted voltages are in phase.

Diagram shown in the original SVG worksheet.

  1. Find the voltage across the free terminals when the undotted end of winding 1 is joined to the dotted end of winding 2.

  2. Find the magnitude when the two undotted ends are instead joined, and explain the difference.

Question 8 - Solution

Secondary polarity controls whether series voltages add or subtract

Diagram shown in the original SVG worksheet.

(a) Method and calculation

V1=(40)(.500)=20.0V,V2=(60)(.500)=30.0V.V_1=(40)(.500)=20.0\,V,\quad V_2=(60)(.500)=30.0\,V.Vaiding=V1+V2=50.0V.\boxed{V_{\mathrm{aiding}}=V_1+V_2=50.0\,V}.

(b) Interpretation and further calculation

Vd1−Vd2=V1−V2when undotted ends are common.V_{d1}-V_{d2}=V_1-V_2\quad\text{when undotted ends are common}.|Vopposing|=|20−30|=10.0V.\boxed{|V_{\mathrm{opposing}}|=|20-30|=10.0\,V}.

Physical check

Turn counts determine magnitudes; winding polarity determines the sign in the terminal sum.