LC Oscillations, Qualitatively — Question 2

Section 31-1 · Physics pages 4974–4975

Question 2 The direction of energy flow follows the product of charge and current At an instant in an ideal LC loop, q is positive and i = ˙q is negative. Use L˙i = −q/C. C L q i = ˙q Schematic; labels, not drawing lengths, specify the data. (a) Determine the signs of both energy rates. (b) If the next observed state has q negative but i still negative, determine which energy store is now growing.
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Question 2 - Solution The direction of energy flow follows the product of charge and current C L q i = ˙q (a) Method and calculation ˙UC = (q/C)i < 0, ˙UL = Li˙i = −qi/C > 0. ˙UC + ˙UL = 0 . (b) Interpretation and further calculation q < 0, i < 0 ⇒qi > 0. ˙UC > 0, ˙UL < 0 . Physical check Current direction alone does not identify the direction of energy transfer; capacitor polarity matters too.

Question 2

The direction of energy flow follows the product of charge and current

At an instant in an ideal LC loop, q is positive and i=q̇i=\dot q is negative. Use Li̇=−q/CL\dot i=-q/C.

Diagram shown in the original SVG worksheet.

  1. Determine the signs of both energy rates.

  2. If the next observed state has q negative but i still negative, determine which energy store is now growing.

Question 2 - Solution

The direction of energy flow follows the product of charge and current

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U̇C=(q/C)i<0,U̇L=Lii̇=−qi/C>0.\dot U_C=(q/C)i<0,\quad\dot U_L=Li\dot i=-qi/C>0.U̇C+U̇L=0.\boxed{\dot U_C+\dot U_L=0}.

(b) Interpretation and further calculation

q<0,i<0⇒qi>0.q<0,\ i<0\Rightarrow qi>0.U̇C>0,U̇L<0.\boxed{\dot U_C>0,\quad\dot U_L<0}.

Physical check

Current direction alone does not identify the direction of energy transfer; capacitor polarity matters too.