LC Oscillations, Qualitatively — Question 1

Section 31-1 · Physics pages 4972–4973

Question 1 A discharged capacitor can coexist with the largest circuit current An ideal LC loop starts with capacitor charge Q and zero current. Use U = q2/(2C) + Li2/2 and define i = ˙q on the initially positive plate. C L q i = ˙q Schematic; labels, not drawing lengths, specify the data. (a) Find the current magnitude when the capacitor first reaches zero charge. (b) Determine whether the motion stops there and give the sign of the next capacitor charge.
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Question 1 - Solution A discharged capacitor can coexist with the largest circuit current C L q i = ˙q (a) Method and calculation U = Q2/(2C) = LI2 max/2. Imax = Q/ √ LC . (b) Interpretation and further calculation q = 0, i = −Imax̸ = 0 ⇒q(t + dt) ≃−Imaxdt. q(t + dt) < 0; UC = 0, UL = U . Physical check Zero capacitor voltage is not zero total energy; the inductor continues transferring charge.

Question 1

A discharged capacitor can coexist with the largest circuit current

An ideal LC loop starts with capacitor charge Q and zero current. Use U=q2/(2C)+Li2/2U=q^2/(2C)+Li^2/2 and define i=q̇i=\dot q on the initially positive plate.

Diagram shown in the original SVG worksheet.

  1. Find the current magnitude when the capacitor first reaches zero charge.

  2. Determine whether the motion stops there and give the sign of the next capacitor charge.

Question 1 - Solution

A discharged capacitor can coexist with the largest circuit current

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U=Q2/(2C)=LImax⁡2/2.U=Q^2/(2C)=LI_{\max}^2/2.Imax=Q/LC.\boxed{I_{\max}=Q/\sqrt{LC}}.

(b) Interpretation and further calculation

q=0,i=−Imax≠0⇒q(t+dt)≃−Imaxdt.q=0,\quad i=-I_{\max}\ne0\Rightarrow q(t+dt)\simeq-I_{\max}dt.q(t+dt)<0;UC=0,UL=U.\boxed{q(t+dt)<0;\quad U_C=0,\ U_L=U}.

Physical check

Zero capacitor voltage is not zero total energy; the inductor continues transferring charge.