Induced Electric Fields — Question 5

Section 30-5 · Physics pages 4840–4841

Question 5 Changing enclosed flux transfers angular momentum to a constrained charge A particle of charge q and mass m is constrained to a frictionless circular track of radius r outside an axially symmetric changing-flux region. The enclosed magnetic flux changes by DeltaPhi. The track force is radial and the particle starts at rest. a r axial B(t) Schematic; labels, not drawing lengths, specify the data. (a) Find the change in angular momentum about the axis. (b) Find final kinetic energy, neglecting radiation and the particle back-reaction on the source.
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Question 5 - Solution Changing enclosed flux transfers angular momentum to a constrained charge a r axial B(t) (a) Method and calculation 2πrEϕ = −˙Φ, ˙Lz = rqEϕ = −q ˙Φ/(2π). ∆Lz = −q∆Φ/(2π) . (b) Interpretation and further calculation Kf = L2 z 2mr2 . Kf = q2(∆Φ)2 8π2mr2 . Physical check A magnetic force, if present at the track, is radial and does no work. The induced electric field transfers the energy.

Question 5

Changing enclosed flux transfers angular momentum to a constrained charge

A particle of charge q and mass m is constrained to a frictionless circular track of radius r outside an axially symmetric changing-flux region. The enclosed magnetic flux changes by DeltaPhi. The track force is radial and the particle starts at rest.

Diagram shown in the original SVG worksheet.

  1. Find the change in angular momentum about the axis.

  2. Find final kinetic energy, neglecting radiation and the particle back-reaction on the source.

Question 5 - Solution

Changing enclosed flux transfers angular momentum to a constrained charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

2πrEϕ=−Φ̇,L̇z=rqEϕ=−qΦ̇/(2π).2\pi rE_\phi=-\dot\Phi,\quad\dot L_z=rqE_\phi=-q\dot\Phi/(2\pi).ΔLz=−qΔΦ/(2π).\boxed{\Delta L_z=-q\Delta\Phi/(2\pi)}.

(b) Interpretation and further calculation

Kf=Lz22mr2.K_f=\frac{L_z^2}{2mr^2}.Kf=q2(ΔΦ)28π2mr2.\boxed{K_f=\frac{q^2(\Delta\Phi)^2}{8\pi^2mr^2}}.

Physical check

A magnetic force, if present at the track, is radial and does no work. The induced electric field transfers the energy.