Induced Electric Fields — Question 4

Section 30-5 · Physics pages 4838–4839

Question 4 Two paths between the same points can give different electric work Inside a uniform cylindrical field increasing at rate beta, the induced field is Eϕ = −βr/2. A charge q is moved quasistatically from (r,0) to (-r,0), either on the upper semicircle counterclockwise or on the lower semicircle clockwise. Treat beta as constant. A B r Schematic; labels, not drawing lengths, specify the data. (a) Find the work done by the induced electric field along each path. (b) Find their difference and compare with a full-loop circulation.
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Question 4 - Solution Two paths between the same points can give different electric work A B r (a) Method and calculation Wupper = q Z π 0 Eϕr dϕ = −qπβr2/2 . Wlower = q Z −π 0 Eϕr dϕ = +qπβr2/2 . (b) Interpretation and further calculation Wupper −Wlower = −qπβr2. Wupper −Wlower = q I⃗ E · d⃗ℓ= −q ˙Φ . Physical check A single-valued electrostatic potential cannot represent this induced field around the entire loop.

Question 4

Two paths between the same points can give different electric work

Inside a uniform cylindrical field increasing at rate beta, the induced field is Eϕ=−βr/2E_\phi=-\beta r/2. A charge q is moved quasistatically from (r,0) to (-r,0), either on the upper semicircle counterclockwise or on the lower semicircle clockwise. Treat beta as constant.

Diagram shown in the original SVG worksheet.

  1. Find the work done by the induced electric field along each path.

  2. Find their difference and compare with a full-loop circulation.

Question 4 - Solution

Two paths between the same points can give different electric work

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Wupper=q∫0πEϕrdϕ=−qπβr2/2.W_{\mathrm{upper}}=q\int_0^\pi E_\phi r\,d\phi=\boxed{-q\pi\beta r^2/2}.Wlower=q∫0−πEϕrdϕ=+qπβr2/2.W_{\mathrm{lower}}=q\int_0^{-\pi}E_\phi r\,d\phi=\boxed{+q\pi\beta r^2/2}.

(b) Interpretation and further calculation

Wupper−Wlower=−qπβr2.W_{\mathrm{upper}}-W_{\mathrm{lower}}=-q\pi\beta r^2.Wupper−Wlower=q∮E→⋅dℓ→=−qΦ̇.\boxed{W_{\mathrm{upper}}-W_{\mathrm{lower}}=q\oint\vec E\cdot d\vec\ell=-q\dot\Phi}.

Physical check

A single-valued electrostatic potential cannot represent this induced field around the entire loop.