A Current-Carrying Coil as a Magnetic Dipole — Question 10

Section 29-5 · Physics pages 4750–4751

Question 10 The best coil radius depends on whether turns or wire length is held fixed A thin circular coil must maximize the field at a prescribed axial distance z>0. Its radius R is adjustable and B = µ0NIR2/[2(R2 + z2)3/2]. Ignore leads, heating and winding thickness. Current I remains fixed. Use vacuum permeability µ0 ≃4π × 10−7 T m/A where numerical values are needed. z R P z Schematic; labels, not drawing lengths, specify the data. (a) Find the optimal R when N is fixed. (b) Instead hold total wire length Lw fixed, with N = Lw/(2πR) treated as continuous. Find the new optimal R and compare the design constraints.
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Question 10 - Solution The best coil radius depends on whether turns or wire length is held fixed z R P z (a) Method and calculation d dR ln B = 2 R − 3R R2 + z2 = 0 ⇒2z2 −R2 = 0. Ropt = √ 2z (N, I fixed); B →0 as R →0 or ∞. (b) Interpretation and further calculation B = µ0ILwR 4π(R2 + z2)3/2 , d dR ln B = 1 R − 3R R2 + z2 = 0. Ropt = z/ √ 2 (Lw, I fixed). The wire-length constraint reduces the available turns as the radius grows; an actual winding must also satisfy integer-turn and geometric constraints. Physical check Both stationary points are maxima under their respective constraints. Optimizing a field without stating what is held fixed gives an incomplete design problem.

Question 10

The best coil radius depends on whether turns or wire length is held fixed

A thin circular coil must maximize the field at a prescribed axial distance z>0. Its radius R is adjustable and B=μ0NIR2/[2(R2+z2)3/2]B=\mu_0NIR^2/[2(R^2+z^2)^{3/2}]. Ignore leads, heating and winding thickness. Current I remains fixed. Use vacuum permeability μ0≃4π×10−7Tm/A\mu_0\simeq4\pi\times10^{-7}\,\mathrm{T\,m/A} where numerical values are needed.

Diagram shown in the original SVG worksheet.

  1. Find the optimal R when N is fixed.

  2. Instead hold total wire length Lw fixed, with N=Lw/(2πR)N=L_w/(2\pi R) treated as continuous. Find the new optimal R and compare the design constraints.

Question 10 - Solution

The best coil radius depends on whether turns or wire length is held fixed

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ddRln⁡B=2R−3RR2+z2=0⇒2z2−R2=0.\frac d{dR}\ln B=\frac2R-\frac{3R}{R^2+z^2}=0\Rightarrow2z^2-R^2=0.Ropt=2z(N,I fixed);B→0 as R→0 or ∞.\boxed{R_{\mathrm{opt}}=\sqrt2z}\quad(N,I\text{ fixed});\quad B\to0\text{ as }R\to0\text{ or }\infty.

(b) Interpretation and further calculation

B=μ0ILwR4π(R2+z2)3/2,ddRln⁡B=1R−3RR2+z2=0.B=\frac{\mu_0IL_wR}{4\pi(R^2+z^2)^{3/2}},\quad\frac d{dR}\ln B=\frac1R-\frac{3R}{R^2+z^2}=0.Ropt=z/2(Lw,I fixed).\boxed{R_{\mathrm{opt}}=z/\sqrt2}\quad(L_w,I\text{ fixed}).The wire-length constraint reduces the available turns as the radius grows; an actual winding must also satisfy integer-turn and geometric constraints.

Physical check

Both stationary points are maxima under their respective constraints. Optimizing a field without stating what is held fixed gives an incomplete design problem.