A Current-Carrying Coil as a Magnetic Dipole — Question 9

Section 29-5 · Physics pages 4748–4749

Question 9 Spatially separated opposite dipoles retain an inverse-fourth-power far field Two small coils are modeled as point dipoles: +µˆz at z=+a and −µˆz at z=-a. Consider z>a on the axis, much farther from each coil than its radius. Use the signed axial point-dipole field Bz = µ0µz/(2πr3). Use vacuum permeability µ0 ≃4π × 10−7 T m/A where numerical values are needed. z −⃗µ +⃗µ −a +a P Schematic; labels, not drawing lengths, specify the data. (a) Write the net axial field and derive its leading far-field form for z much larger than a. (b) Compare its decay with that of one dipole and explain why zero total moment does not imply zero field everywhere.
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Question 9 - Solution Spatially separated opposite dipoles retain an inverse-fourth-power far field z −⃗µ +⃗µ −a +a P (a) Method and calculation Bz(z) = µ0µ 2π [ 1 (z −a)3 − 1 (z + a)3 ] . 1 (z ∓a)3 = 1 z3 ( 1 ± 3a z + O(a2/z2) ) ⇒Bz ≃3µ0µa πz4 . (b) Interpretation and further calculation Bsingle = µ0µ 2πz3 , Bz/Bsingle ≃6a/z .⃗ µtotal = 0, but (z −a)−3̸ = (z + a)−3. The leading dipole term cancels; unequal source distances leave a higher-order field. Physical check Separated dipoles lack the coplanar symmetry of concentric opposed coils, so their first surviving axial far-field term has a different power.

Question 9

Spatially separated opposite dipoles retain an inverse-fourth-power far field

Two small coils are modeled as point dipoles: +μẑ+\mu\hat z at z=+a and −μẑ-\mu\hat z at z=-a. Consider z>a on the axis, much farther from each coil than its radius. Use the signed axial point-dipole field Bz=μ0μz/(2πr3)B_z=\mu_0\mu_z/(2\pi r^3). Use vacuum permeability μ0≃4π×10−7Tm/A\mu_0\simeq4\pi\times10^{-7}\,\mathrm{T\,m/A} where numerical values are needed.

Diagram shown in the original SVG worksheet.

  1. Write the net axial field and derive its leading far-field form for z much larger than a.

  2. Compare its decay with that of one dipole and explain why zero total moment does not imply zero field everywhere.

Question 9 - Solution

Spatially separated opposite dipoles retain an inverse-fourth-power far field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Bz(z)=μ0μ2π[1(z−a)3−1(z+a)3].B_z(z)=\frac{\mu_0\mu}{2\pi}\left[\frac1{(z-a)^3}-\frac1{(z+a)^3}\right].1(z∓a)3=1z3(1±3az+O(a2/z2))⇒Bz≃3μ0μaπz4.\frac1{(z\mp a)^3}=\frac1{z^3}\left(1\pm\frac{3a}{z}+O(a^2/z^2)\right)\Rightarrow\boxed{B_z\simeq\frac{3\mu_0\mu a}{\pi z^4}}.

(b) Interpretation and further calculation

Bsingle=μ0μ2πz3,Bz/Bsingle≃6a/z.B_{\mathrm{single}}=\frac{\mu_0\mu}{2\pi z^3},\quad\boxed{B_z/B_{\mathrm{single}}\simeq6a/z}.μ→total=0,but(z−a)−3≠(z+a)−3.\vec\mu_{\mathrm{total}}=0,\quad\text{but}\quad(z-a)^{-3}\ne(z+a)^{-3}.The leading dipole term cancels; unequal source distances leave a higher-order field.

Physical check

Separated dipoles lack the coplanar symmetry of concentric opposed coils, so their first surviving axial far-field term has a different power.