Cyclotrons and Synchrotrons — Question 7

Section 28-6 · Physics pages 4584–4585

Question 7 A fixed-radius synchrotron must ramp its bending field with momentum rather than kinetic energy alone A synchrotron maintains bending radius rho for particles of rest mass m and charge magnitude q. Use the supplied relations p = qBρ and p2c2 = K(K + 2mc2). ρ RF fixed orbit Schematic; labels, not drawing lengths, specify the data. (a) Derive the field required at kinetic energy K. (b) Find the leading field scaling for K much smaller and much larger than mc squared, and compare the field changes when K doubles in each limit.
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Question 7 - Solution A fixed-radius synchrotron must ramp its bending field with momentum rather than kinetic energy alone ρ RF fixed orbit (a) Method and calculation p = 1 c √ K(K + 2mc2). B(K) = √ K(K + 2mc2) qcρ . (b) Interpretation and further calculation K ≪mc2 : B ≃ √ 2mK qρ , B(2K)/B(K) ≃ √ 2. K ≫mc2 : B ≃K qcρ, B(2K)/B(K) ≃2. Physical check Magnetic rigidity is momentum per charge; equal kinetic-energy increments do not generally require equal field increments.

Question 7

A fixed-radius synchrotron must ramp its bending field with momentum rather than kinetic energy alone

A synchrotron maintains bending radius rho for particles of rest mass m and charge magnitude q. Use the supplied relations p=qBρp=qB\rho and p2c2=K(K+2mc2)p^2c^2=K(K+2mc^2).

Diagram shown in the original SVG worksheet.

  1. Derive the field required at kinetic energy K.

  2. Find the leading field scaling for K much smaller and much larger than mc squared, and compare the field changes when K doubles in each limit.

Question 7 - Solution

A fixed-radius synchrotron must ramp its bending field with momentum rather than kinetic energy alone

Diagram shown in the original SVG worksheet.

(a) Method and calculation

p=1cK(K+2mc2).p=\frac1c\sqrt{K(K+2mc^2)}.B(K)=K(K+2mc2)qcρ.B(K)=\frac{\sqrt{K(K+2mc^2)}}{qc\rho}.

(b) Interpretation and further calculation

K≪mc2:B≃2mKqρ,B(2K)/B(K)≃2.K\ll mc^2:\quad B\simeq\frac{\sqrt{2mK}}{q\rho},\quad B(2K)/B(K)\simeq\sqrt2.K≫mc2:B≃Kqcρ,B(2K)/B(K)≃2.K\gg mc^2:\quad B\simeq\frac K{qc\rho},\quad B(2K)/B(K)\simeq2.

Physical check

Magnetic rigidity is momentum per charge; equal kinetic-energy increments do not generally require equal field increments.