Cyclotrons and Synchrotrons — Question 6

Section 28-6 · Physics pages 4582–4583

Question 6 Maintaining a fixed cyclotron frequency requires a radius-dependent relativistic field An idealized isochronous cyclotron is designed to keep angular frequency omega0 fixed as energy rises. Use r = γmv/(qB) and γ = (1 −v2/c2)−1/2. Ignore focusing and edge-field requirements. dee 1 dee 2 alternating gap voltage⃗ B into page Schematic; labels, not drawing lengths, specify the data. (a) Derive B(r) in terms of B0 = mω0/q. (b) Find B/B0 when omega0 r=.600c and explain the limiting radius in this model.
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Question 6 - Solution Maintaining a fixed cyclotron frequency requires a radius-dependent relativistic field dee 1 dee 2 alternating gap voltage⃗ B into page (a) Method and calculation v = ω0r, ω0 = qB γm ⇒B = γB0. B(r) = B0 √ 1 −(ω0r/c)2 . (b) Interpretation and further calculation ω0r = .600c ⇒B/B0 = 1/ √ 1 −.6002 = 1.25. r < c/ω0; B(r) →∞as r →(c/ω0)−. Physical check This is a timing condition only; a complete accelerator also needs transverse confinement and practical magnet limits.

Question 6

Maintaining a fixed cyclotron frequency requires a radius-dependent relativistic field

An idealized isochronous cyclotron is designed to keep angular frequency omega0 fixed as energy rises. Use r=γmv/(qB)r=\gamma mv/(qB) and γ=(1−v2/c2)−1/2\gamma=(1-v^2/c^2)^{-1/2}. Ignore focusing and edge-field requirements.

Diagram shown in the original SVG worksheet.

  1. Derive B(r) in terms of B0=mω0/qB_0=m\omega_0/q.

  2. Find B/B0 when omega0 r=.600c and explain the limiting radius in this model.

Question 6 - Solution

Maintaining a fixed cyclotron frequency requires a radius-dependent relativistic field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

v=ω0r,ω0=qBγm⇒B=γB0.v=\omega_0r,\quad\omega_0=\frac{qB}{\gamma m}\Rightarrow B=\gamma B_0.B(r)=B01−(ω0r/c)2.B(r)=\frac{B_0}{\sqrt{1-(\omega_0r/c)^2}}.

(b) Interpretation and further calculation

ω0r=.600c⇒B/B0=1/1−.6002=1.25.\omega_0r=.600c\Rightarrow B/B_0=1/\sqrt{1-.600^2}=1.25.r<c/ω0;B(r)→∞ as r→(c/ω0)−.r<c/\omega_0;\quad B(r)\to\infty\text{ as }r\to(c/\omega_0)^-.

Physical check

This is a timing condition only; a complete accelerator also needs transverse confinement and practical magnet limits.