RC Circuits — Question 10

Section 27-8 · Physics pages 4470–4471

Question 10 Timing to a fractional threshold separates RC tolerance from source amplitude An initially uncharged capacitor charges through R from a constant positive source E. A comparator changes state when vC reaches fE, where 0<f<1. Nominal values are R0=100 kilohm, C0=1.00 microfarad and f=.800. Hard component tolerances are plus or minus 2 percent in R and 5 percent in C; f is exact. + − E R C + − Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Derive the trigger time and calculate its nominal value. (b) Find the exact earliest and latest times allowed by the tolerances, and explain whether changing E changes the ideal trigger time.
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Question 10 - Solution Timing to a fractional threshold separates RC tolerance from source amplitude + − E R C + − (a) Method and calculation fE = E(1 −e−t/(RC)) ⇒t = −RC ln(1 −f). t0 = (.100 s) ln 5 = .160944 s. (b) Interpretation and further calculation tmin = t0(.98)(.95) = .931t0 = .1498387 s. tmax = t0(1.02)(1.05) = 1.071t0 = .1723708 s. E cancels because the threshold tracks a fixed fraction of the same source voltage. Physical check Hard tolerance limits multiply at their extrema; a root-sum-square estimate would require a statistical model.

Question 10

Timing to a fractional threshold separates RC tolerance from source amplitude

An initially uncharged capacitor charges through R from a constant positive source E. A comparator changes state when vC reaches fE, where 0<f<1. Nominal values are R0=100 kilohm, C0=1.00 microfarad and f=.800. Hard component tolerances are plus or minus 2 percent in R and 5 percent in C; f is exact.

Diagram shown in the original SVG worksheet.

  1. Derive the trigger time and calculate its nominal value.

  2. Find the exact earliest and latest times allowed by the tolerances, and explain whether changing E changes the ideal trigger time.

Question 10 - Solution

Timing to a fractional threshold separates RC tolerance from source amplitude

Diagram shown in the original SVG worksheet.

(a) Method and calculation

fE=E(1−e−t/(RC))⇒t=−RCln⁡(1−f).fE=E(1-e^{-t/(RC)})\Rightarrow t=-RC\ln(1-f).t0=(.100s)ln⁡5=.160944s.t_0=(.100\,\mathrm s)\ln5=.160944\,\mathrm s.

(b) Interpretation and further calculation

tmin=t0(.98)(.95)=.931t0=.1498387s.t_{\min}=t_0(.98)(.95)=.931t_0=.1498387\,\mathrm s.tmax=t0(1.02)(1.05)=1.071t0=.1723708s.t_{\max}=t_0(1.02)(1.05)=1.071t_0=.1723708\,\mathrm s.E cancels because the threshold tracks a fixed fraction of the same source voltage.

Physical check

Hard tolerance limits multiply at their extrema; a root-sum-square estimate would require a statistical model.