RC Circuits — Question 9

Section 27-8 · Physics pages 4468–4469

Question 9 Periodic switching settles into two reproducible capacitor-voltage limits An ideal input alternates between E and zero, spending duration T at each level. It drives a series R and shunt C with tau=RC. Consider the periodic steady state. Let L be the capacitor voltage just before each high interval and H just after it; set a = e−T/τ. t vin E T 2T input to series R, shunt C Schematic; labels, not drawing lengths, specify the data. (a) Derive H, L and the peak-to-peak ripple. (b) Find the time-averaged capacitor voltage over a complete cycle and the small-T limit of the ripple.
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Question 9 - Solution Periodic switching settles into two reproducible capacitor-voltage limits t vin E T 2T input to series R, shunt C (a) Method and calculation H = E + (L −E)a, L = aH ⇒H = E 1 + a, L = aE 1 + a. ∆V = H −L = E 1 −a 1 + a. (b) Interpretation and further calculation τ⟨˙vC⟩+ ⟨vC⟩= ⟨vin⟩⇒⟨vC⟩= E/2. T/τ ≪1 : a ≃1 −T/τ, ∆V ≃ET 2τ . Physical check Periodic steady state requires zero net capacitor charge change per cycle, not zero instantaneous current.

Question 9

Periodic switching settles into two reproducible capacitor-voltage limits

An ideal input alternates between E and zero, spending duration T at each level. It drives a series R and shunt C with tau=RC. Consider the periodic steady state. Let L be the capacitor voltage just before each high interval and H just after it; set a=e−T/τa=e^{-T/\tau}.

Diagram shown in the original SVG worksheet.

  1. Derive H, L and the peak-to-peak ripple.

  2. Find the time-averaged capacitor voltage over a complete cycle and the small-T limit of the ripple.

Question 9 - Solution

Periodic switching settles into two reproducible capacitor-voltage limits

Diagram shown in the original SVG worksheet.

(a) Method and calculation

H=E+(L−E)a,L=aH⇒H=E1+a,L=aE1+a.H=E+(L-E)a,\quad L=aH\Rightarrow H=\frac E{1+a},\quad L=\frac{aE}{1+a}.ΔV=H−L=E1−a1+a.\Delta V=H-L=E\frac{1-a}{1+a}.

(b) Interpretation and further calculation

τ⟨v̇C⟩+⟨vC⟩=⟨vin⟩⇒⟨vC⟩=E/2.\tau\langle\dot v_C\rangle+\langle v_C\rangle=\langle v_{\mathrm{in}}\rangle\Rightarrow\langle v_C\rangle=E/2.T/τ≪1:a≃1−T/τ,ΔV≃ET2τ.T/\tau\ll1:\quad a\simeq1-T/\tau,\quad\Delta V\simeq\frac{ET}{2\tau}.

Physical check

Periodic steady state requires zero net capacitor charge change per cycle, not zero instantaneous current.