The Ammeter and the Voltmeter — Question 2

Section 27-7 · Physics pages 4434–4435

Question 2 A series multiplier sets a voltmeter range through the movement current A movement has resistance Rg=1.00 kilohm and full-scale current Ig=100 microampere. A series resistor Rs makes a 20.0 V full-scale voltmeter. Rs G A C Rg, Ig Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Find Rs and the total input resistance. (b) Find the movement voltage and the power dissipated in Rs at full scale.
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Question 2 - Solution A series multiplier sets a voltmeter range through the movement current Rs G A C Rg, Ig (a) Method and calculation RV = VFS/Ig = 20/(10−4) = 200 kΩ. Rs = RV −Rg = 199 kΩ. (b) Interpretation and further calculation Vg = IgRg = .100 V, Vs = 20 −.100 = 19.9 V. Ps = I2 gRs = 1.99 × 10−3 W. Physical check A large input resistance reduces the extra current drawn by a voltmeter.

Question 2

A series multiplier sets a voltmeter range through the movement current

A movement has resistance Rg=1.00 kilohm and full-scale current Ig=100 microampere. A series resistor Rs makes a 20.0 V full-scale voltmeter.

Diagram shown in the original SVG worksheet.

  1. Find Rs and the total input resistance.

  2. Find the movement voltage and the power dissipated in Rs at full scale.

Question 2 - Solution

A series multiplier sets a voltmeter range through the movement current

Diagram shown in the original SVG worksheet.

(a) Method and calculation

RV=VFS/Ig=20/(10−4)=200kΩ.R_V=V_{\mathrm{FS}}/I_g=20/(10^{-4})=200\,\mathrm{k\Omega}.Rs=RV−Rg=199kΩ.R_s=R_V-R_g=199\,\mathrm{k\Omega}.

(b) Interpretation and further calculation

Vg=IgRg=.100V,Vs=20−.100=19.9V.V_g=I_gR_g=.100\,\mathrm V,\quad V_s=20-.100=19.9\,\mathrm V.Ps=Ig2Rs=1.99×10−3W.P_s=I_g^2R_s=1.99\times10^{-3}\,\mathrm W.

Physical check

A large input resistance reduces the extra current drawn by a voltmeter.