The Ammeter and the Voltmeter — Question 1

Section 27-7 · Physics pages 4432–4433

Question 1 A shunt converts a sensitive movement into a high-current ammeter A meter movement has full-scale current Ig=50.0 microampere and resistance Rg=2.00 kilohm. A parallel shunt is to produce a 5.00 A full-scale ammeter. G Rs A B movement: Rg, Ig Circuit connections and marked polarities define the model; wire lengths are schematic. (a) Find the shunt resistance and full-scale voltage burden across the instrument. (b) Find the effective ammeter resistance and shunt heating at full scale.
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Question 1 - Solution A shunt converts a sensitive movement into a high-current ammeter G Rs A B movement: Rg, Ig (a) Method and calculation Vg = IgRg = (50.0 × 10−6)(2000) = .100 V. Rs = IgRg IFS −Ig = .100 5 −.000050 = .0200002 Ω. (b) Interpretation and further calculation RA = Vg/IFS = .0200 Ω. Ps = (IFS −Ig)Vg = .499995 W ≃.500 W. Physical check The shunt carries almost all the current, but both parallel paths have the same voltage.

Question 1

A shunt converts a sensitive movement into a high-current ammeter

A meter movement has full-scale current Ig=50.0 microampere and resistance Rg=2.00 kilohm. A parallel shunt is to produce a 5.00 A full-scale ammeter.

Diagram shown in the original SVG worksheet.

  1. Find the shunt resistance and full-scale voltage burden across the instrument.

  2. Find the effective ammeter resistance and shunt heating at full scale.

Question 1 - Solution

A shunt converts a sensitive movement into a high-current ammeter

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Vg=IgRg=(50.0×10−6)(2000)=.100V.V_g=I_gR_g=(50.0\times10^{-6})(2000)=.100\,\mathrm V.Rs=IgRgIFS−Ig=.1005−.000050=.0200002Ω.R_s=\frac{I_gR_g}{I_{\mathrm{FS}}-I_g}=\frac{.100}{5-.000050}=.0200002\,\Omega.

(b) Interpretation and further calculation

RA=Vg/IFS=.0200Ω.R_A=V_g/I_{\mathrm{FS}}=.0200\,\Omega.Ps=(IFS−Ig)Vg=.499995W≃.500W.P_s=(I_{\mathrm{FS}}-I_g)V_g=.499995\,\mathrm W\simeq.500\,\mathrm W.

Physical check

The shunt carries almost all the current, but both parallel paths have the same voltage.