Semiconductors — Question 10

Section 26-7 · Physics pages 4290–4291

Question 10 A moving hole represents a sequence of electron hops A one-dimensional chain of lattice spacing a has one vacant electron site. Each time a neighboring electron hops right into the vacancy, the vacancy moves one site left. Such steps occur at mean rate f. Treat the vacancy as a hole of charge +e. electron hole Schematic; labels, not drawing lengths, specify the data. (a) Find hole drift velocity and the current contribution of a uniform hole density p through area A. (b) For a periodic chain with N sites and exactly one hole, find the mean conventional current through one fixed bond and verify it using circulation time.
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Question 10 - Solution A moving hole represents a sequence of electron hops electron hole (a) Method and calculation vh = −af, Jh = epvh = −epaf. Ih = JhA = −epAaf. (b) Interpretation and further calculation Tcircuit = N/f, Ibond = −e Tcircuit = −ef/N. pA = 1/(Na) ⇒Ih = −e(1/Na)af = −ef/N. Physical check An electron moving right and the corresponding hole moving left carry the same conventional-current sign.

Question 10

A moving hole represents a sequence of electron hops

A one-dimensional chain of lattice spacing a has one vacant electron site. Each time a neighboring electron hops right into the vacancy, the vacancy moves one site left. Such steps occur at mean rate f. Treat the vacancy as a hole of charge +e.

Diagram shown in the original SVG worksheet.

  1. Find hole drift velocity and the current contribution of a uniform hole density p through area A.

  2. For a periodic chain with N sites and exactly one hole, find the mean conventional current through one fixed bond and verify it using circulation time.

Question 10 - Solution

A moving hole represents a sequence of electron hops

Diagram shown in the original SVG worksheet.

(a) Method and calculation

vh=−af,Jh=epvh=−epaf.v_h=-af,\quad J_h=epv_h=-epaf.Ih=JhA=−epAaf.I_h=J_hA=-epAaf.

(b) Interpretation and further calculation

Tcircuit=N/f,Ibond=−eTcircuit=−ef/N.T_{\mathrm{circuit}}=N/f,\quad I_{\mathrm{bond}}=\frac{-e}{T_{\mathrm{circuit}}}=-ef/N.pA=1/(Na)⇒Ih=−e(1/Na)af=−ef/N.pA=1/(Na)\Rightarrow I_h=-e(1/Na)af=-ef/N.

Physical check

An electron moving right and the corresponding hole moving left carry the same conventional-current sign.