Semiconductors — Question 9

Section 26-7 · Physics pages 4288–4289

Question 9 The minimum conductivity at fixed mass action need not occur at equal carrier densities At fixed temperature, np = n2 i and the positive mobilities µn, µp are fixed. Treat n as a variable set by doping and use σ = e(nµn + pµp). n/ni σ Axes and labels specify the model; the sketch is schematic. (a) Find n and p that minimize conductivity. (b) Find the minimum conductivity and compare it with the intrinsic value at n=p=ni.
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Question 9 - Solution The minimum conductivity at fixed mass action need not occur at equal carrier densities n/ni σ (a) Method and calculation σ(n) = e ( µnn + µpn2 i /n ) , dσ/dn = e(µn −µpn2 i /n2). n∗= ni √ µp/µn, p∗= ni √ µn/µp, d2σ/dn2 > 0. (b) Interpretation and further calculation σmin = 2eni√µnµp. σintrinsic −σmin = eni(√µn −√µp)2 ≥0. Physical check The optimum balances the two conductivity contributions, not necessarily the two carrier densities.

Question 9

The minimum conductivity at fixed mass action need not occur at equal carrier densities

At fixed temperature, np=ni2np=n_i^2 and the positive mobilities μn,μp\mu_n,\mu_p are fixed. Treat n as a variable set by doping and use σ=e(nμn+pμp)\sigma=e(n\mu_n+p\mu_p).

Diagram shown in the original SVG worksheet.

  1. Find n and p that minimize conductivity.

  2. Find the minimum conductivity and compare it with the intrinsic value at n=p=ni.

Question 9 - Solution

The minimum conductivity at fixed mass action need not occur at equal carrier densities

Diagram shown in the original SVG worksheet.

(a) Method and calculation

σ(n)=e(μnn+μpni2/n),dσ/dn=e(μn−μpni2/n2).\sigma(n)=e\left(\mu_nn+\mu_pn_i^2/n\right),\quad d\sigma/dn=e(\mu_n-\mu_pn_i^2/n^2).n*=niμp/μn,p*=niμn/μp,d2σ/dn2>0.n_*=n_i\sqrt{\mu_p/\mu_n},\quad p_*=n_i\sqrt{\mu_n/\mu_p},\quad d^2\sigma/dn^2>0.

(b) Interpretation and further calculation

σmin=2eniμnμp.\sigma_{\min}=2en_i\sqrt{\mu_n\mu_p}.σintrinsic−σmin=eni(μn−μp)2≥0.\sigma_{\mathrm{intrinsic}}-\sigma_{\min}=en_i(\sqrt{\mu_n}-\sqrt{\mu_p})^2\ge0.

Physical check

The optimum balances the two conductivity contributions, not necessarily the two carrier densities.