Current Density — Question 9

Section 26-2 · Physics pages 4188–4189

Question 9 An interface mismatch grows a surface charge sheet At a flat interface with normal +ˆx from medium 1 to 2, uniform normal currents are J1n = Ja and J2n = Ja(1 −e−t/τ). Initially the surface charge density is zero. J1n J2n σs Schematic; labels, not drawing lengths, specify the data. (a) Find the surface charge density by applying conservation to a thin pillbox. (b) Find the charge accumulated over area A and its long-time limit.
Show solutionHide solution
Question 9 - Solution An interface mismatch grows a surface charge sheet J1n J2n σs (a) Method and calculation A dσs/dt = A(J1n −J2n) = AJae−t/τ. σs(t) = Jaτ(1 −e−t/τ). (b) Interpretation and further calculation Qs = Aσs = AJaτ(1 −e−t/τ). Qs(∞) = AJaτ, dσs/dt →0. Physical check The pillbox turns volume conservation into a surface-charge boundary condition.

Question 9

An interface mismatch grows a surface charge sheet

At a flat interface with normal +x̂+\hat x from medium 1 to 2, uniform normal currents are J1n=JaJ_{1n}=J_a and J2n=Ja(1−e−t/τ)J_{2n}=J_a(1-e^{-t/\tau}). Initially the surface charge density is zero.

Diagram shown in the original SVG worksheet.

  1. Find the surface charge density by applying conservation to a thin pillbox.

  2. Find the charge accumulated over area A and its long-time limit.

Question 9 - Solution

An interface mismatch grows a surface charge sheet

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Adσs/dt=A(J1n−J2n)=AJae−t/τ.A\,d\sigma_s/dt=A(J_{1n}-J_{2n})=AJ_ae^{-t/\tau}.σs(t)=Jaτ(1−e−t/τ).\sigma_s(t)=J_a\tau(1-e^{-t/\tau}).

(b) Interpretation and further calculation

Qs=Aσs=AJaτ(1−e−t/τ).Q_s=A\sigma_s=AJ_a\tau(1-e^{-t/\tau}).Qs(∞)=AJaτ,dσs/dt→0.Q_s(\infty)=AJ_a\tau,\quad d\sigma_s/dt\to0.

Physical check

The pillbox turns volume conservation into a surface-charge boundary condition.