Current Density — Question 8

Section 26-2 · Physics pages 4186–4187

Question 8 A radial steady current spreads over growing spherical surfaces An inner spherical electrode injects total current I radially outward into a medium between radii a and b. Assume spherical symmetry and no charge accumulation. Jr a b Schematic; labels, not drawing lengths, specify the data. (a) Find⃗J(r) and the ratio of its magnitudes at the two electrodes. (b) For carriers of charge q > 0 and constant number density n, find their radial drift time from a to b.
Show solutionHide solution
Question 8 - Solution A radial steady current spreads over growing spherical surfaces Jr a b (a) Method and calculation I = I⃗ J · d⃗A = 4πr2Jr(r).⃗ J = I 4πr2 ˆr, J(b)/J(a) = (a/b)2. (b) Interpretation and further calculation vr = Jr/(nq) = I/(4πnqr2). t = Z b a dr vr = 4πnq 3I (b3 −a3). Physical check Constant total current is compatible with a position-dependent local density.

Question 8

A radial steady current spreads over growing spherical surfaces

An inner spherical electrode injects total current I radially outward into a medium between radii a and b. Assume spherical symmetry and no charge accumulation.

Diagram shown in the original SVG worksheet.

  1. Find J→(r)\vec J(r) and the ratio of its magnitudes at the two electrodes.

  2. For carriers of charge q>0q>0 and constant number density n, find their radial drift time from a to b.

Question 8 - Solution

A radial steady current spreads over growing spherical surfaces

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I=∮J→⋅dA→=4πr2Jr(r).I=\oint\vec J\cdot d\vec A=4\pi r^2J_r(r).J→=I4πr2r̂,J(b)/J(a)=(a/b)2.\vec J=\frac{I}{4\pi r^2}\hat r,\quad J(b)/J(a)=(a/b)^2.

(b) Interpretation and further calculation

vr=Jr/(nq)=I/(4πnqr2).v_r=J_r/(nq)=I/(4\pi nq r^2).t=∫abdrvr=4πnq3I(b3−a3).t=\int_a^b\frac{dr}{v_r}=\frac{4\pi nq}{3I}(b^3-a^3).

Physical check

Constant total current is compatible with a position-dependent local density.