Dielectrics and Gauss' Law — Question 9

Section 25-7 · Physics pages 4148–4149

Question 9 A constant radial field in a graded spherical dielectric requires free bulk charge In a spherical annulus a<r<b, relative permittivity is κ(r) = κ0r/a. A desired field is E = E0ˆr, with E0>0. An inner conductor of radius a supplies charge Qa. Use Gauss law for D. a b ˆr Schematic; labels, not drawing lengths, specify the data. (a) Find the free volume density required in the annulus and the inner conductor charge. (b) Find the voltage drop and total enclosed free charge just inside r=b; verify the latter by adding volume and conductor charges.
Show solutionHide solution
Question 9 - Solution A constant radial field in a graded spherical dielectric requires free bulk charge a b ˆr (a) Method and calculation Dr = ϵ0κ0E0r/a ⇒ρf = 1 r2 d dr(r2Dr) = 3ϵ0κ0E0 a . Qa = 4πa2Dr(a) = 4πϵ0κ0E0a2. (b) Interpretation and further calculation Va −Vb = E0(b −a), Qf(< b) = 4πb2Dr(b) = 4πϵ0κ0E0b3/a. Qa + 4πρf 3 (b3 −a3) = 4πϵ0κ0E0b3/a. Physical check A radial field of constant magnitude has nonzero divergence; it is not equivalent to a spatially uniform Cartesian vector field.

Question 9

A constant radial field in a graded spherical dielectric requires free bulk charge

In a spherical annulus a<r<b, relative permittivity is κ(r)=κ0r/a\kappa(r)=\kappa_0r/a. A desired field is 𝑬=E0𝒓̂\mathbf E=E_0\hat{\mathbf r}, with E0>0. An inner conductor of radius a supplies charge Qa. Use Gauss law for D.

Diagram shown in the original SVG worksheet.

  1. Find the free volume density required in the annulus and the inner conductor charge.

  2. Find the voltage drop and total enclosed free charge just inside r=b; verify the latter by adding volume and conductor charges.

Question 9 - Solution

A constant radial field in a graded spherical dielectric requires free bulk charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Dr=ϵ0κ0E0r/a⇒ρf=1r2ddr(r2Dr)=3ϵ0κ0E0a.D_r=\epsilon_0\kappa_0E_0r/a\Rightarrow\rho_f=\frac1{r^2}\frac d{dr}(r^2D_r)=\frac{3\epsilon_0\kappa_0E_0}{a}.Qa=4πa2Dr(a)=4πϵ0κ0E0a2.Q_a=4\pi a^2D_r(a)=4\pi\epsilon_0\kappa_0E_0a^2.

(b) Interpretation and further calculation

Va−Vb=E0(b−a),Qf(<b)=4πb2Dr(b)=4πϵ0κ0E0b3/a.V_a-V_b=E_0(b-a),\quad Q_f(<b)=4\pi b^2D_r(b)=4\pi\epsilon_0\kappa_0E_0b^3/a.Qa+4πρf3(b3−a3)=4πϵ0κ0E0b3/a.Q_a+\frac{4\pi\rho_f}{3}(b^3-a^3)=4\pi\epsilon_0\kappa_0E_0b^3/a.

Physical check

A radial field of constant magnitude has nonzero divergence; it is not equivalent to a spatially uniform Cartesian vector field.