Dielectrics and Gauss' Law — Question 8

Section 25-7 · Physics pages 4146–4147

Question 8 A dielectric sphere responds to its applied field and its own depolarizing field A homogeneous dielectric sphere of radius R has relative permittivity kappa and no free charge. A distant source applies uniform field E0. Use the supplied result that uniform polarization P creates internal field −P/(3ϵ0) and the constitutive law P = ϵ0(κ −1)Ein. R E0 Cross-section of concentric spherical surfaces; labels specify radii. (a) Solve self-consistently for the interior field and polarization. (b) Find its total dipole moment and bound surface density as a function of angle theta from E0.
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Question 8 - Solution A dielectric sphere responds to its applied field and its own depolarizing field R E0 (a) Method and calculation Ein = E0 −P/(3ϵ0) ⇒Ein = 3 κ + 2E0. P = 3ϵ0(κ −1) κ + 2 E0. (b) Interpretation and further calculation psphere = 4πR3 3 P = 4πϵ0R3 κ −1 κ + 2E0. σb(θ) = P cos θ, ρb = 0. Physical check The internal field is not E0/kappa; that reduction applies to a different boundary geometry and source constraint.

Question 8

A dielectric sphere responds to its applied field and its own depolarizing field

A homogeneous dielectric sphere of radius R has relative permittivity kappa and no free charge. A distant source applies uniform field E0. Use the supplied result that uniform polarization P creates internal field −𝑷/(3ϵ0)-\mathbf P/(3\epsilon_0) and the constitutive law 𝑷=ϵ0(κ−1)𝑬in\mathbf P=\epsilon_0(\kappa-1)\mathbf E_{\mathrm{in}}.

Diagram shown in the original SVG worksheet.

  1. Solve self-consistently for the interior field and polarization.

  2. Find its total dipole moment and bound surface density as a function of angle theta from E0.

Question 8 - Solution

A dielectric sphere responds to its applied field and its own depolarizing field

Diagram shown in the original SVG worksheet.

(a) Method and calculation

𝑬in=𝑬0−𝑷/(3ϵ0)⇒𝑬in=3κ+2𝑬0.\mathbf E_{\mathrm{in}}=\mathbf E_0-\mathbf P/(3\epsilon_0)\Rightarrow\mathbf E_{\mathrm{in}}=\frac3{\kappa+2}\mathbf E_0.𝑷=3ϵ0(κ−1)κ+2𝑬0.\mathbf P=\frac{3\epsilon_0(\kappa-1)}{\kappa+2}\mathbf E_0.

(b) Interpretation and further calculation

𝒑sphere=4πR33𝑷=4πϵ0R3κ−1κ+2𝑬0.\mathbf p_{\mathrm{sphere}}=\frac{4\pi R^3}{3}\mathbf P=4\pi\epsilon_0R^3\frac{\kappa-1}{\kappa+2}\mathbf E_0.σb(θ)=Pcos⁡θ,ρb=0.\sigma_b(\theta)=P\cos\theta,\quad\rho_b=0.

Physical check

The internal field is not E0/kappa; that reduction applies to a different boundary geometry and source constraint.