Capacitor with a Dielectric — Question 9

Section 25-5 · Physics pages 4108–4109

Question 9 Thermal expansion can cancel the first-order dielectric temperature coefficient A plate capacitor is filled with a dielectric obeying κ(T) = κ0(1 + β∆T). Every geometric length scales by 1 + α∆T. Treat these supplied laws as exact over the small interval and use C = κϵ0A/d. A B d κ Ideal plate cross-section; fringing is neglected unless stated. (a) Find the exact capacitance ratio and its first-order temperature coefficient. (b) Choose beta to cancel first-order drift and find the remaining fractional change.
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Question 9 - Solution Thermal expansion can cancel the first-order dielectric temperature coefficient A B d κ (a) Method and calculation C(T) C(0) = (1 + β∆T)(1 + α∆T)2 1 + α∆T = (1 + β∆T)(1 + α∆T). ∆C C(0) = (α + β)∆T + αβ(∆T)2. (b) Interpretation and further calculation β = −α ⇒1 C dC dT ∆T=0 = 0. ∆C C(0) = −α2(∆T)2. Physical check Cancellation of the linear drift does not remove the quadratic term in the explicitly supplied material and expansion model.

Question 9

Thermal expansion can cancel the first-order dielectric temperature coefficient

A plate capacitor is filled with a dielectric obeying κ(T)=κ0(1+βΔT)\kappa(T)=\kappa_0(1+\beta\Delta T). Every geometric length scales by 1+αΔT1+\alpha\Delta T. Treat these supplied laws as exact over the small interval and use C=κϵ0A/dC=\kappa\epsilon_0A/d.

Diagram shown in the original SVG worksheet.

  1. Find the exact capacitance ratio and its first-order temperature coefficient.

  2. Choose beta to cancel first-order drift and find the remaining fractional change.

Question 9 - Solution

Thermal expansion can cancel the first-order dielectric temperature coefficient

Diagram shown in the original SVG worksheet.

(a) Method and calculation

C(T)C(0)=(1+βΔT)(1+αΔT)21+αΔT=(1+βΔT)(1+αΔT).\frac{C(T)}{C(0)}=(1+\beta\Delta T)\frac{(1+\alpha\Delta T)^2}{1+\alpha\Delta T}=(1+\beta\Delta T)(1+\alpha\Delta T).ΔCC(0)=(α+β)ΔT+αβ(ΔT)2.\frac{\Delta C}{C(0)}=(\alpha+\beta)\Delta T+\alpha\beta(\Delta T)^2.

(b) Interpretation and further calculation

β=−α⇒1CdCdT|ΔT=0=0.\beta=-\alpha\Rightarrow\left.\frac1C\frac{dC}{dT}\right|_{\Delta T=0}=0.ΔCC(0)=−α2(ΔT)2.\frac{\Delta C}{C(0)}=-\alpha^2(\Delta T)^2.

Physical check

Cancellation of the linear drift does not remove the quadratic term in the explicitly supplied material and expansion model.