Potential Due to an Electric Dipole — Question 8

Section 24-7 · Physics pages 3926–3927

Question 8 A dipole pair interaction depends on both moments and their connecting axis Two small ideal dipoles have moments p1 and p2 and center separation R much larger than their physical sizes. Use U = −p2 · E1 and E1 = k[3(p1 · ˆR) ˆR −p1]/R3. p1 p2 R Schematic; labels, not drawing lengths, specify the data. (a) Find U when the moments are parallel to each other and to the connecting axis, then when parallel to each other but perpendicular to that axis. (b) For fixed orientations find the radial force FR = −dU/dR in both cases and classify attraction or repulsion.
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Question 8 - Solution A dipole pair interaction depends on both moments and their connecting axis p1 p2 R (a) Method and calculation U∥= −2kp1p2/R3. U⊥= +kp1p2/R3. (b) Interpretation and further calculation FR,∥= −6kp1p2/R4 < 0 attraction. FR,⊥= +3kp1p2/R4 > 0 repulsion. Physical check Orientations are held fixed when differentiating R; allowing free rotation changes the mechanical problem.

Question 8

A dipole pair interaction depends on both moments and their connecting axis

Two small ideal dipoles have moments p1 and p2 and center separation R much larger than their physical sizes. Use U=−𝒑2⋅𝑬1U=-\mathbf p_2\cdot\mathbf E_1 and 𝑬1=k[3(𝒑1⋅𝑹̂)𝑹̂−𝒑1]/R3\mathbf E_1=k[3(\mathbf p_1\cdot\hat{\mathbf R})\hat{\mathbf R}-\mathbf p_1]/R^3.

Diagram shown in the original SVG worksheet.

  1. Find U when the moments are parallel to each other and to the connecting axis, then when parallel to each other but perpendicular to that axis.

  2. For fixed orientations find the radial force FR=−dU/dRF_R=-dU/dR in both cases and classify attraction or repulsion.

Question 8 - Solution

A dipole pair interaction depends on both moments and their connecting axis

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U∥=−2kp1p2/R3.U_{\parallel}=-2kp_1p_2/R^3.U⟂=+kp1p2/R3.U_{\perp}=+kp_1p_2/R^3.

(b) Interpretation and further calculation

FR,∥=−6kp1p2/R4<0attraction.F_{R,\parallel}=-6kp_1p_2/R^4<0\quad\text{attraction}.FR,⟂=+3kp1p2/R4>0repulsion.F_{R,\perp}=+3kp_1p_2/R^4>0\quad\text{repulsion}.

Physical check

Orientations are held fixed when differentiating R; allowing free rotation changes the mechanical problem.