Potential Due to an Electric Dipole — Question 7

Section 24-7 · Physics pages 3924–3925

Question 7 A dipole translation samples curvature in an external potential A rigid dipole is constrained along x with charges +q at X+d/2 and -q at X-d/2. The external potential is Vext(x) = Ax2, with A positive. Its moment is p=qd directed along positive x. x −q X +q Schematic; labels, not drawing lengths, specify the data. (a) Find the exact external interaction energy as a function of its center X. (b) Find the net force from that energy and verify it by summing the forces on both charges.
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Question 7 - Solution A dipole translation samples curvature in an external potential x −q X +q (a) Method and calculation U = qA[(X + d/2)2 −(X −d/2)2] = 2AqdX. U(X) = 2ApX, FX = −dU/dX = −2Ap. (b) Interpretation and further calculation Ex(x) = −2Ax, Fnet = qEx(X + d/2) −qEx(X −d/2). Fnet = −2Aqd = −2Ap. Physical check The force is nonzero because the external field varies in space; the quadratic potential makes this finite-separation result exact.

Question 7

A dipole translation samples curvature in an external potential

A rigid dipole is constrained along x with charges +q at X+d/2 and -q at X-d/2. The external potential is Vext(x)=Ax2V_{\mathrm{ext}}(x)=Ax^2, with A positive. Its moment is p=qd directed along positive x.

Diagram shown in the original SVG worksheet.

  1. Find the exact external interaction energy as a function of its center X.

  2. Find the net force from that energy and verify it by summing the forces on both charges.

Question 7 - Solution

A dipole translation samples curvature in an external potential

Diagram shown in the original SVG worksheet.

(a) Method and calculation

U=qA[(X+d/2)2−(X−d/2)2]=2AqdX.U=qA[(X+d/2)^2-(X-d/2)^2]=2AqdX.U(X)=2ApX,FX=−dU/dX=−2Ap.U(X)=2ApX,\quad F_X=-dU/dX=-2Ap.

(b) Interpretation and further calculation

Ex(x)=−2Ax,Fnet=qEx(X+d/2)−qEx(X−d/2).E_x(x)=-2Ax,\quad F_{\mathrm{net}}=qE_x(X+d/2)-qE_x(X-d/2).Fnet=−2Aqd=−2Ap.F_{\mathrm{net}}=-2Aqd=-2Ap.

Physical check

The force is nonzero because the external field varies in space; the quadratic potential makes this finite-separation result exact.