Electric Potential Energy — Question 3

Section 24-1 · Physics pages 3796–3797

Question 3 External work includes both stored energy and a kinetic-energy change A particle moves between two points with UB −UA = 12.0 µJ. Its kinetic energy increases from 5.00 to 9.00 µJ. Electric force and one external actuator are the only agents doing work. A B Two different paths between the same endpoints. (a) Find electric work and actuator work. (b) After a separate preparation step, the particle is returned from B to A quasistatically. Find actuator work on this return and on the two specified trips combined, excluding preparation.
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Question 3 - Solution External work includes both stored energy and a kinetic-energy change A B (a) Method and calculation We = −∆U = −12.0 µJ, ∆K = 9.00 −5.00 = 4.00 µJ. Wext = ∆K + ∆U = 16.0 µJ. (b) Interpretation and further calculation Wext,return = UA −UB = −12.0 µJ (∆Kreturn = 0). Wext,total = 16.0 −12.0 = 4.00 µJ. The return is specified as a separate quasistatic process; preparation for it is not included in these two work values. Physical check The common equality Wext = ∆U requires zero kinetic-energy change and no other nonconservative work.

Question 3

External work includes both stored energy and a kinetic-energy change

A particle moves between two points with UB−UA=12.0μU_B-U_A=12.0\,\muJ. Its kinetic energy increases from 5.005.00 to 9.00μ9.00\,\muJ. Electric force and one external actuator are the only agents doing work.

Diagram shown in the original SVG worksheet.

  1. Find electric work and actuator work.

  2. After a separate preparation step, the particle is returned from B to A quasistatically. Find actuator work on this return and on the two specified trips combined, excluding preparation.

Question 3 - Solution

External work includes both stored energy and a kinetic-energy change

Diagram shown in the original SVG worksheet.

(a) Method and calculation

We=−ΔU=−12.0μJ,ΔK=9.00−5.00=4.00μJ.W_e=-\Delta U=-12.0\,\mu\mathrm J,\quad\Delta K=9.00-5.00=4.00\,\mu\mathrm J.Wext=ΔK+ΔU=16.0μJ.W_{\mathrm{ext}}=\Delta K+\Delta U=16.0\,\mu\mathrm J.

(b) Interpretation and further calculation

Wext,return=UA−UB=−12.0μJ(ΔKreturn=0).W_{\mathrm{ext,return}}=U_A-U_B=-12.0\,\mu\mathrm J\quad(\Delta K_{\mathrm{return}}=0).Wext,total=16.0−12.0=4.00μJ.W_{\mathrm{ext,total}}=16.0-12.0=4.00\,\mu\mathrm J.The return is specified as a separate quasistatic process; preparation for it is not included in these two work values.

Physical check

The common equality Wext=ΔUW_{\mathrm{ext}}=\Delta U requires zero kinetic-energy change and no other nonconservative work.