Electric Potential Energy — Question 2

Section 24-1 · Physics pages 3794–3795

Question 2 Three work measurements can expose an inconsistent electrostatic claim For the same fixed test charge in a static field, measured electric works are WA→B = 8.00 µJ and WB→C = −3.00 µJ. A third report claims WA→C = 6.00 µJ. Treat all values as exact. A B C Schematic; labels, not drawing lengths, specify the data. (a) Use potential-energy differences to predict the third work. (b) Calculate the closed-loop work implied by the three reports and identify the required correction if the first two are retained.
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Question 2 - Solution Three work measurements can expose an inconsistent electrostatic claim A B C (a) Method and calculation UB −UA = −8.00 µJ, UC −UB = +3.00 µJ. UC −UA = −5.00 µJ ⇒WA→C = +5.00 µJ. (b) Interpretation and further calculation WA→B→C→A = 8.00 −3.00 −6.00 = −1.00 µJ̸ = 0. WA→C : 6.00 −→5.00 µJ. The exact reports cannot all describe the same conservative electrostatic field. Physical check Any path-dependent mechanical losses must be separated from electric work before testing conservativeness.

Question 2

Three work measurements can expose an inconsistent electrostatic claim

For the same fixed test charge in a static field, measured electric works are WA→B=8.00μW_{A\to B}=8.00\,\muJ and WB→C=−3.00μW_{B\to C}=-3.00\,\muJ. A third report claims WA→C=6.00μW_{A\to C}=6.00\,\muJ. Treat all values as exact.

Diagram shown in the original SVG worksheet.

  1. Use potential-energy differences to predict the third work.

  2. Calculate the closed-loop work implied by the three reports and identify the required correction if the first two are retained.

Question 2 - Solution

Three work measurements can expose an inconsistent electrostatic claim

Diagram shown in the original SVG worksheet.

(a) Method and calculation

UB−UA=−8.00μJ,UC−UB=+3.00μJ.U_B-U_A=-8.00\,\mu\mathrm J,\quad U_C-U_B=+3.00\,\mu\mathrm J.UC−UA=−5.00μJ⇒WA→C=+5.00μJ.U_C-U_A=-5.00\,\mu\mathrm J\Rightarrow W_{A\to C}=+5.00\,\mu\mathrm J.

(b) Interpretation and further calculation

WA→B→C→A=8.00−3.00−6.00=−1.00μJ≠0.W_{A\to B\to C\to A}=8.00-3.00-6.00=-1.00\,\mu\mathrm J\ne0.WA→C:6.00→5.00μJ.W_{A\to C}:\quad6.00\longrightarrow5.00\,\mu\mathrm J.The exact reports cannot all describe the same conservative electrostatic field.

Physical check

Any path-dependent mechanical losses must be separated from electric work before testing conservativeness.