The Electric Field Due to an Electric Dipole — Question 6

Section 22-4 · Physics pages 3542–3543

Question 6 A zero axial component occurs on a cone where the field remains nonzero For a point dipole pˆz, use Ez = A(3 cos2 θ −1) and |E| = A √ 1 + 3 cos2 θ, with A = kp/r3 > 0. z Schematic; labels, not drawing lengths, specify the data. (a) Find both polar angles where the field has zero z component. (b) Find the magnitude there and decide whether either cone is a surface of field nulls.
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Question 6 - Solution A zero axial component occurs on a cone where the field remains nonzero z (a) Method and calculation Ez = 0 ⇒cos2 θ = 1/3. θ1 = cos−1(1/ √ 3) ≈54.7356◦, θ2 = 180◦−θ1 ≈125.2644◦. (b) Interpretation and further calculation |E| = A √ 1 + 3(1/3) = √ 2A > 0. |E| ≥A for every angle at finite r. Only one component vanishes; a nonzero ideal dipole has no finite off-source field null. Physical check The two dashed cones are shown in cross-section; a component condition does not determine a zero vector.

Question 6

A zero axial component occurs on a cone where the field remains nonzero

For a point dipole p𝒛̂p\hat{\mathbf z}, use Ez=A(3cos⁡2θ−1)E_z=A(3\cos^2\theta-1) and |𝑬|=A1+3cos⁡2θ|\mathbf E|=A\sqrt{1+3\cos^2\theta}, with A=kp/r3>0A=kp/r^3>0.

Diagram shown in the original SVG worksheet.

  1. Find both polar angles where the field has zero z component.

  2. Find the magnitude there and decide whether either cone is a surface of field nulls.

Question 6 - Solution

A zero axial component occurs on a cone where the field remains nonzero

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Ez=0⇒cos⁡2θ=1/3.E_z=0\Rightarrow\cos^2\theta=1/3.θ1=cos⁡−1(1/3)≈54.7356∘,θ2=180∘−θ1≈125.2644∘.\theta_1=\cos^{-1}(1/\sqrt3)\approx54.7356^\circ,\quad\theta_2=180^\circ-\theta_1\approx125.2644^\circ.

(b) Interpretation and further calculation

|𝑬|=A1+3(1/3)=2A>0.|\mathbf E|=A\sqrt{1+3(1/3)}=\sqrt2A>0.|𝑬|≥Afor every angle at finite r.|\mathbf E|\ge A\quad\text{for every angle at finite }r.Only one component vanishes; a nonzero ideal dipole has no finite off-source field null.

Physical check

The two dashed cones are shown in cross-section; a component condition does not determine a zero vector.