The Electric Field Due to an Electric Dipole — Question 5

Section 22-4 · Physics pages 3540–3541

Question 5 Angular dipole components determine a field direction distinct from the observation ray A point-dipole approximation has moment pˆz. At polar angle θ, use Er = 2A cos θ, Eθ = A sin θ, with A = kp/r3 > 0 and ˆθ pointing toward increasing polar angle. p P θ Schematic; labels, not drawing lengths, specify the data. (a) At θ = 60◦, find Er, Eθ, the magnitude and the angle of E from the outward radial direction. (b) Find the z component using ˆz = cos θˆr −sin θˆθ.
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Question 5 - Solution Angular dipole components determine a field direction distinct from the observation ray p P θ (a) Method and calculation Er = A, Eθ = √ 3 2 A, |E| = √ 7 2 A. α = tan−1(Eθ/Er) = tan−1( √ 3/2) ≈40.8934◦. (b) Interpretation and further calculation Ez = Er cos θ −Eθ sin θ = A(3 cos2 θ −1). θ = 60◦: Ez = −A/4. A positive radial component does not imply a positive component along the dipole axis. Physical check The radial basis rotates with observation direction; it is not the fixed z basis.

Question 5

Angular dipole components determine a field direction distinct from the observation ray

A point-dipole approximation has moment p𝒛̂p\hat{\mathbf z}. At polar angle θ\theta, use Er=2Acos⁡θE_r=2A\cos\theta, Eθ=Asin⁡θE_\theta=A\sin\theta, with A=kp/r3>0A=kp/r^3>0 and 𝜽̂\hat{\boldsymbol\theta} pointing toward increasing polar angle.

Diagram shown in the original SVG worksheet.

  1. At θ=60∘\theta=60^\circ, find Er,EθE_r,E_\theta, the magnitude and the angle of E from the outward radial direction.

  2. Find the z component using 𝒛̂=cos⁡θ𝒓̂−sin⁡θ𝜽̂\hat{\mathbf z}=\cos\theta\hat{\mathbf r}-\sin\theta\hat{\boldsymbol\theta}.

Question 5 - Solution

Angular dipole components determine a field direction distinct from the observation ray

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Er=A,Eθ=32A,|𝑬|=72A.E_r=A,\quad E_\theta=\tfrac{\sqrt3}2A,\quad |\mathbf E|=\tfrac{\sqrt7}2A.α=tan⁡−1(Eθ/Er)=tan⁡−1(3/2)≈40.8934∘.\alpha=\tan^{-1}(E_\theta/E_r)=\tan^{-1}(\sqrt3/2)\approx40.8934^\circ.

(b) Interpretation and further calculation

Ez=Ercos⁡θ−Eθsin⁡θ=A(3cos⁡2θ−1).E_z=E_r\cos\theta-E_\theta\sin\theta=A(3\cos^2\theta-1).θ=60∘:Ez=−A/4.\theta=60^\circ:\quad E_z=-A/4.A positive radial component does not imply a positive component along the dipole axis.

Physical check

The radial basis rotates with observation direction; it is not the fixed z basis.