Sources of Musical Sound — Question 7

Section 17-6 · Physics pages 2744–2745

Question 7 A bottle resonator uses a gas spring and a neck mass A Helmholtz model treats a neck air slug of effective length ℓand area A as mass m = ρAℓ. Its displacement x compresses a cavity of volume V , giving ∆p = BAx/V . Let c2 = B/ρ, A = 3.0 × 10−4 m2, ℓ= 0.030 m, V = 1.0 × 10−3 m3 and c = 340 m/s. V A, ℓ Cavity and narrow neck; effective neck length includes any stated end correction. (a) Derive the resonance frequency and evaluate it. (b) How does frequency change if cavity volume quadruples? State the main wavelength condition behind this lumped model.
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Question 7 - Solution A bottle resonator uses a gas spring and a neck mass V A, ℓ (a) Method and calculation The restoring force is −A∆p, so keff= BA2 V , ω2 = keff m = c2A V ℓ. f = c 2π √ A V ℓ= 340 2π √ 10 = 171.12 Hz. (b) Interpretation and further calculation With the neck unchanged, f ∝V −1/2, so quadrupling volume halves the frequency to 85.56 Hz. The cavity dimensions and neck length should be small relative to wavelength so cavity pressure is nearly uniform and neck air moves approximately as one slug. Here λ = c/f ≃1.99 m. Physical check The expression has units of frequency because A/(V ℓ) has units m−2. Radiation loss and viscous damping are neglected.

Question 7

A bottle resonator uses a gas spring and a neck mass

A Helmholtz model treats a neck air slug of effective length ℓ\ell and area AA as mass m=ρAℓm=\rho A\ell. Its displacement xx compresses a cavity of volume VV, giving Δp=BAx/V\Delta p=B Ax/V. Let c2=B/ρc^2=B/\rho, A=3.0×10−4m2A=3.0\times10^{-4}\,\mathrm{m^2}, ℓ=0.030m\ell=0.030\,\mathrm m, V=1.0×10−3m3V=1.0\times10^{-3}\,\mathrm{m^3} and c=340m/sc=340\,\mathrm{m/s}.

Diagram shown in the original SVG worksheet.

  1. Derive the resonance frequency and evaluate it.

  2. How does frequency change if cavity volume quadruples? State the main wavelength condition behind this lumped model.

Question 7 - Solution

A bottle resonator uses a gas spring and a neck mass

Diagram shown in the original SVG worksheet.

(a) Method and calculation

The restoring force is −AΔp-A\Delta p, sokeff=BA2V,ω2=keffm=c2AVℓ.k_{\mathrm{eff}}=\frac{BA^2}{V},\quad\omega^2=\frac{k_{\mathrm{eff}}}m=\frac{c^2A}{V\ell}.f=c2πAVℓ=3402π10=171.12Hz.f=\frac c{2\pi}\sqrt{\frac{A}{V\ell}}=\frac{340}{2\pi}\sqrt{10}=171.12\,\mathrm{Hz}.

(b) Interpretation and further calculation

With the neck unchanged, f∝V−1/2f\propto V^{-1/2}, so quadrupling volume halves the frequency to 85.56Hz85.56\,\mathrm{Hz}. The cavity dimensions and neck length should be small relative to wavelength so cavity pressure is nearly uniform and neck air moves approximately as one slug. Here λ=c/f≃1.99m\lambda=c/f\simeq1.99\,\mathrm m.

Physical check

The expression has units of frequency because A/(Vℓ)A/(V\ell) has units m−2\mathrm{m^{-2}}. Radiation loss and viscous damping are neglected.