Sources of Musical Sound — Question 6

Section 17-6 · Physics pages 2742–2743

Question 6 Pressure and velocity microphones see complementary pipe modes An ideal open-open tube has pressure modes pn = Pn sin(nπx/L) cos ωnt. A pressure sensor and a nonloading axial-velocity sensor are both placed at the midpoint. Use ρ0ut = −px and ωn = cnπ/L. L open open Both nonloading sensors are at the tube midpoint; pressure and velocity mode shapes differ. (a) Derive the velocity mode shape. (b) Which of modes n = 1 through 6 can each sensor detect at the midpoint? Explain why a missing pressure peak does not prove that the mode is absent.
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Question 6 - Solution Pressure and velocity microphones see complementary pipe modes L open open (a) Method and calculation Differentiating pressure gives px = Pn nπ L cos(nπx/L) cos ωnt. Integrating the momentum equation in time, with no steady flow, gives un = −Pn ρ0c cos(nπx/L) sin ωnt. (b) Interpretation and further calculation At x = L/2, the pressure factor is sin(nπ/2), nonzero for n = 1, 3, 5. The velocity factor is cos(nπ/2), nonzero for n = 2, 4, 6. Even modes can store energy and move fluid at the midpoint while producing zero pressure there. Sensor coupling, not just allowed eigenfrequency, determines visibility. Physical check The two sensor sets are complementary here because the pressure and velocity spatial factors differ by a quarter wavelength.

Question 6

Pressure and velocity microphones see complementary pipe modes

An ideal open-open tube has pressure modes pn=Pnsin⁡(nπx/L)cos⁡ωntp_n=P_n\sin(n\pi x/L)\cos\omega_nt. A pressure sensor and a nonloading axial-velocity sensor are both placed at the midpoint. Use ρ0ut=−px\rho_0u_t=-p_x and ωn=cnπ/L\omega_n=cn\pi/L.

Diagram shown in the original SVG worksheet.

  1. Derive the velocity mode shape.

  2. Which of modes n=1n=1 through 66 can each sensor detect at the midpoint? Explain why a missing pressure peak does not prove that the mode is absent.

Question 6 - Solution

Pressure and velocity microphones see complementary pipe modes

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Differentiating pressure givespx=PnnπLcos⁡(nπx/L)cos⁡ωnt.p_x=P_n\frac{n\pi}{L}\cos(n\pi x/L)\cos\omega_nt.Integrating the momentum equation in time, with no steady flow, givesun=−Pnρ0ccos⁡(nπx/L)sin⁡ωnt.u_n=-\frac{P_n}{\rho_0c}\cos(n\pi x/L)\sin\omega_nt.

(b) Interpretation and further calculation

At x=L/2x=L/2, the pressure factor is sin⁡(nπ/2)\sin(n\pi/2), nonzero for n=1,3,5n=1,3,5. The velocity factor is cos⁡(nπ/2)\cos(n\pi/2), nonzero for n=2,4,6n=2,4,6. Even modes can store energy and move fluid at the midpoint while producing zero pressure there. Sensor coupling, not just allowed eigenfrequency, determines visibility.

Physical check

The two sensor sets are complementary here because the pressure and velocity spatial factors differ by a quarter wavelength.