What Is a Fluid? — Question 4

Section 14-1 · Physics pages 2058–2059

Question 4 An opened partition distinguishes two fluids A rigid vessel has two equal 1.0 L compartments separated by a removable partition. A sample initially fills the left compartment; the right is evacuated. Consider two separate experiments: an idealized nonvolatile liquid with negligible compressibility, and a gas. Remove the partition and wait for equilibrium at the original temperature. For the liquid, gravity acts downward and the compartments have equal horizontal base areas; ignore capillarity. sample vacuum removable partition Initial vessel; the left compartment contains the sample. Schematic. (a) Compare the final volume occupied by each sample. If the initial liquid depth is h, what is its final depth? (b) Both samples adapt to container shape. Why does that fact alone fail to distinguish a liquid from a gas, or to define all fluids?
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Question 4 - Solution An opened partition distinguishes two fluids sample vacuum removable partition (a) Derivation and calculation Let each compartment have base area Ab. Incompressibility gives Vℓ,f = Vℓ,i = Abh = 1.0 L. 2Abhf = Abh ⇒hf = h/2 . Vg,f = 2.0 L , Vℓ,f = 1.0 L . (b) Result and interpretation With unchanged mass, ρℓ,f ≃ρℓ,i, ρg,f = m 2Vg,i = 1 2ρg,i. Shape adaptation occurs in both fluids and can also occur in a deformed solid. Sustained-shear response distinguishes ordinary fluids from solids; volume response distinguishes the specified liquid and gas. Physical check The liquid occupies half the total vessel volume, leaving space above its free surface.

Question 4

An opened partition distinguishes two fluids

A rigid vessel has two equal 1.0L1.0\,\mathrm{L} compartments separated by a removable partition. A sample initially fills the left compartment; the right is evacuated. Consider two separate experiments: an idealized nonvolatile liquid with negligible compressibility, and a gas. Remove the partition and wait for equilibrium at the original temperature. For the liquid, gravity acts downward and the compartments have equal horizontal base areas; ignore capillarity.

Diagram shown in the original SVG worksheet.

  1. Compare the final volume occupied by each sample. If the initial liquid depth is hh, what is its final depth?

  2. Both samples adapt to container shape. Why does that fact alone fail to distinguish a liquid from a gas, or to define all fluids?

Question 4 - Solution

An opened partition distinguishes two fluids

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

Let each compartment have base area AbA_b. Incompressibility givesVℓ,f=Vℓ,i=Abh=1.0L.V_{\ell,f}=V_{\ell,i}=A_bh=1.0\,\mathrm L.2Abhf=Abh⇒hf=h/2.2A_bh_f=A_bh\Rightarrow\boxed{h_f=h/2}.Vg,f=2.0L,Vℓ,f=1.0L.\boxed{V_{g,f}=2.0\,\mathrm L},\qquad\boxed{V_{\ell,f}=1.0\,\mathrm L}.

(b) Result and interpretation

With unchanged mass,ρℓ,f≃ρℓ,i,ρg,f=m2Vg,i=12ρg,i.\rho_{\ell,f}\simeq\rho_{\ell,i},\qquad\rho_{g,f}=\frac{m}{2V_{g,i}}=\frac12\rho_{g,i}.Shape adaptation occurs in both fluids and can also occur in a deformed solid. Sustained-shear response distinguishes ordinary fluids from solids; volume response distinguishes the specified liquid and gas.

Physical check

The liquid occupies half the total vessel volume, leaving space above its free surface.