What Is a Fluid? — Question 3

Section 14-1 · Physics pages 2056–2057

Question 3 Separate a wall force into its meaningful parts A small planar wall patch touches an ordinary fluid at rest. Neglect surface tension and other interfacial effects. In Cartesian coordinates, the outward unit normal from the fluid is ˆn = (3ˆi + 4ˆj)/5. A proposed force exerted by the fluid on the patch is F = (10ˆi + 5ˆj) N. Let ˆt = (−4ˆi + 3ˆj)/5 be a tangent. ˆn ˆt fluid wall Directions are shown in the xy plane; unit-vector arrows use the same scale. (a) Compute the signed normal and tangential components. Is this force compatible with the stated static-fluid model? (b) Find the force vector that retains the proposed normal component but removes the incompatibility. Explain why a nonzero normal force is allowed.
Show solutionHide solution
Question 3 - Solution Separate a wall force into its meaningful parts ˆn ˆt fluid wall (a) Derivation and calculation ˆn · ˆt = 0, |ˆn| = |ˆt| = 1. Fn = F · ˆn = 10(3/5) + 5(4/5) = 10 N . Ft = F · ˆt = 10(−4/5) + 5(3/5) = −5 N . The nonzero tangential force is incompatible with the stated static-fluid model. (b) Result and interpretation F⊥= Fnˆn = (6ˆi + 8ˆj) N . F −F⊥= (4ˆi −3ˆj) N = −5ˆt N. Normal compression is allowed; static shear resistance is excluded. Physical check The corrected vector has magnitude 10 N and zero projection on the tangent.

Question 3

Separate a wall force into its meaningful parts

A small planar wall patch touches an ordinary fluid at rest. Neglect surface tension and other interfacial effects. In Cartesian coordinates, the outward unit normal from the fluid is 𝒏̂=(3𝒊̂+4𝒋̂)/5\hat{\mathbf n}=(3\hat{\mathbf i}+4\hat{\mathbf j})/5. A proposed force exerted by the fluid on the patch is 𝑭=(10𝒊̂+5𝒋̂)N\mathbf F=(10\hat{\mathbf i}+5\hat{\mathbf j})\,\mathrm{N}. Let 𝒕̂=(−4𝒊̂+3𝒋̂)/5\hat{\mathbf t}=(-4\hat{\mathbf i}+3\hat{\mathbf j})/5 be a tangent.

Diagram shown in the original SVG worksheet.

  1. Compute the signed normal and tangential components. Is this force compatible with the stated static-fluid model?

  2. Find the force vector that retains the proposed normal component but removes the incompatibility. Explain why a nonzero normal force is allowed.

Question 3 - Solution

Separate a wall force into its meaningful parts

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

𝒏̂⋅𝒕̂=0,|𝒏̂|=|𝒕̂|=1.\hat{\mathbf n}\cdot\hat{\mathbf t}=0,\qquad |\hat{\mathbf n}|=|\hat{\mathbf t}|=1.Fn=𝑭⋅𝒏̂=10(3/5)+5(4/5)=10N.\boxed{F_n=\mathbf F\cdot\hat{\mathbf n}=10(3/5)+5(4/5)=10\,\mathrm N}.Ft=𝑭⋅𝒕̂=10(−4/5)+5(3/5)=−5N.\boxed{F_t=\mathbf F\cdot\hat{\mathbf t}=10(-4/5)+5(3/5)=-5\,\mathrm N}.The nonzero tangential force is incompatible with the stated static-fluid model.

(b) Result and interpretation

𝑭⟂=Fn𝒏̂=(6𝒊̂+8𝒋̂)N.\boxed{\mathbf F_\perp=F_n\hat{\mathbf n}=(6\hat{\mathbf i}+8\hat{\mathbf j})\,\mathrm N}.𝑭−𝑭⟂=(4𝒊̂−3𝒋̂)N=−5𝒕̂N.\mathbf F-\mathbf F_\perp=(4\hat{\mathbf i}-3\hat{\mathbf j})\,\mathrm N=-5\hat{\mathbf t}\,\mathrm N.Normal compression is allowed; static shear resistance is excluded.

Physical check

The corrected vector has magnitude 10 N and zero projection on the tangent.