The Requirements of Equilibrium — Question 1

Section 12-2 · Physics pages 1792–1793

Question 1 A balancing force can leave an uncancelled moment A planar rigid body receives⃗F1 = (3, 0) N at (0, 0) m and⃗F2 = (−3, 0) N at (0, 1) m. No other force or torque acts. 3 N 3 N 1 m Schematic; labels, not drawing lengths, specify the data. (a) Find the force and torque resultants. (b) What pure couple must be added for static equilibrium if the body starts at rest?
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Question 1 - Solution A balancing force can leave an uncancelled moment 3 N 3 N 1 m (a) Derivation and calculation The resultant force vanishes:⃗ Fnet = (3, 0) + (−3, 0) =⃗0 . Taking counterclockwise torque as positive, τz = ∑ (xiFiy −yiFix) = 0 −[1(−3)] = +3 N m . The system is a nonzero couple, despite force balance. (b) Result and interpretation Add a pure clockwise couple τadd = −3 N m ,⃗ Fadd =⃗0. Then ∑⃗ F =⃗0, ∑ τz = 3 −3 = 0. With initial rest, both translational and rotational static-equilibrium requirements hold. Physical check A couple changes the net moment without changing the force resultant.

Question 1

A balancing force can leave an uncancelled moment

A planar rigid body receives F→1=(3,0)N\vec F_1=(3,0)\,\mathrm N at (0,0)m(0,0)\,\mathrm m and F→2=(−3,0)N\vec F_2=(-3,0)\,\mathrm N at (0,1)m(0,1)\,\mathrm m. No other force or torque acts.

Diagram shown in the original SVG worksheet.

  1. Find the force and torque resultants.

  2. What pure couple must be added for static equilibrium if the body starts at rest?

Question 1 - Solution

A balancing force can leave an uncancelled moment

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

The resultant force vanishes: F→net=(3,0)+(−3,0)=0→.\vec F_{\mathrm{net}}=(3,0)+(-3,0)=\boxed{\vec0}. Taking counterclockwise torque as positive, τz=∑(xiFiy−yiFix)=0−[1(−3)]=+3Nm.\tau_z=\sum(x_iF_{iy}-y_iF_{ix})=0-[1(-3)] =\boxed{+3\ \mathrm{N\,m}}. The system is a nonzero couple, despite force balance.

(b) Result and interpretation

Add a pure clockwise couple τadd=−3Nm,F→add=0→.\boxed{\tau_{\mathrm{add}}=-3\ \mathrm{N\,m}},\qquad\vec F_{\mathrm{add}}=\vec0. Then ∑F→=0→,∑τz=3−3=0.\sum\vec F=\vec0,\quad\sum\tau_z=3-3=0. With initial rest, both translational and rotational static-equilibrium requirements hold.

Physical check

A couple changes the net moment without changing the force resultant.