The Rotational Variables — Question 9

Section 10-1 · Physics pages 1388–1389

Question 9 A short arc measures an angle only after units are settled A pointer tip at radius 0.30 m traces 0.12 m of circular arc. A student inserts the resulting angle as degrees into a calculation that requires radians. x y + r Viewed along the fixed axis; counterclockwise is positive. (a) Find the angle in radians and degrees. (b) If the arc is measured within [0.118, 0.122] m and the radius within [0.295, 0.305] m, find sharp angle bounds in radians.
Show solutionHide solution
Question 9 - Solution A short arc measures an angle only after units are settled x y + r (a) Derivation and calculation The arc formula requires radian measure: θ = s r = 0.12 0.30 = 0.400 rad . θdeg = 0.400180 π = 22.92◦. Inserting 22.92 into s = rθ without conversion would overestimate the arc by 180/π. (b) Result and interpretation For positive independent intervals, ∂(s/r)/∂s > 0 and ∂(s/r)/∂r < 0. Therefore θmin = 0.118 0.305 = 0.386885, θmax = 0.122 0.295 = 0.413559. 0.3869 ≤θ ≤0.4136 rad . Each extreme is attainable at the corresponding opposite endpoint pair. Physical check The nominal value 0.400 rad lies within the sharp bounds.

Question 9

A short arc measures an angle only after units are settled

A pointer tip at radius 0.30m0.30\,\mathrm m traces 0.12m0.12\,\mathrm m of circular arc. A student inserts the resulting angle as degrees into a calculation that requires radians.

Diagram shown in the original SVG worksheet.

  1. Find the angle in radians and degrees.

  2. If the arc is measured within [0.118,0.122]m[0.118,0.122]\,\mathrm m and the radius within [0.295,0.305]m[0.295,0.305]\,\mathrm m, find sharp angle bounds in radians.

Question 9 - Solution

A short arc measures an angle only after units are settled

Diagram shown in the original SVG worksheet.

(a) Derivation and calculation

The arc formula requires radian measure: θ=sr=0.120.30=0.400rad.\theta=\frac sr=\frac{0.12}{0.30}=\boxed{0.400\ \mathrm{rad}}. θdeg=0.400180π=22.92∘.\theta_{\mathrm{deg}}=0.400\frac{180}{\pi}=\boxed{22.92^\circ}. Inserting 22.9222.92 into s=rθs=r\theta without conversion would overestimate the arc by 180/π180/\pi.

(b) Result and interpretation

For positive independent intervals, ∂(s/r)/∂s>0\partial(s/r)/\partial s>0 and ∂(s/r)/∂r<0\partial(s/r)/\partial r<0. Therefore θmin=0.1180.305=0.386885,θmax=0.1220.295=0.413559.\theta_{\min}=\frac{0.118}{0.305}=0.386885,\qquad \theta_{\max}=\frac{0.122}{0.295}=0.413559. 0.3869≤θ≤0.4136rad.\boxed{0.3869\le\theta\le0.4136\ \mathrm{rad}}. Each extreme is attainable at the corresponding opposite endpoint pair.

Physical check

The nominal value 0.4000.400 rad lies within the sharp bounds.