Polar Coordinates — Question 7

Section 10-6 · Calculus pages 1833–1834

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Question 7

Problem

Find the Cartesian equation corresponding to θ=2π/3\theta=2\pi/3 and explain why rr must be unrestricted.

Diagram shown in the original SVG worksheet.

Question 7 – Solution

Diagram shown in the original SVG worksheet.

Solution

  1. Use the polar–Cartesian relationships x=rcos⁡θ,y=rsin⁡θ,r2=x2+y2.x=r\cos\theta,\qquad y=r\sin\theta,\qquad r^2=x^2+y^2. Equivalent polar coordinates satisfy (r,θ)=(r,θ+2kπ)=(−r,θ+(2k+1)π).(r,\theta)=(r,\theta+2k\pi)=(-r,\theta+(2k+1)\pi).

  2. Apply the identity that matches the requested conversion, symmetry test, or intersection, and then check the resulting point or curve in the original polar equation.

  3. The line has slope tan⁡(2π/3)=−3\tan(2\pi/3)=-\sqrt3, so y=−3xy=-\sqrt3x.

  4. Allowing negative rr supplies the opposite ray and therefore the entire line.